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Marrrta [24]
3 years ago
9

What is it that lives if it is fed, and dies if you give it a drink?

Physics
1 answer:
IceJOKER [234]3 years ago
6 0
A fire because you feed it wood, it lives longer but if you give it a drink, water, then it dies.
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a flowerpot falls from a windowsill 25m above the sidewalk how fast is the flowerpot moving when it strikes the ground
Mariana [72]

s = 25m

v = ?

a = 9.81m/s²

v² = u² + 2as

v² = 0 + 2x9.81x25

v² = 490.5

v = √490.5

= 22.15m/s

3 0
3 years ago
A box of mass m1 rests on a smooth, horizontal floor next to a box of mass m2. Suppose the force of 20.0 N pushes on two boxes o
meriva

Answer:

Explanation:

Given

acceleration of system a =1.2 m/s^2

Normal Force N=4.45 N

Force exerted F=20 N

Thus

F=(m_1+m_2)a

\frac{20}{1.2}=m_1+m_2

16.67=m_1+m_2-------1

Normal reaction N=m_2a

4.45=m_2\times 1.2

m_2=3.70 kg

therefore m_1=16.67-3.70

m_1=12.96 kg

8 0
3 years ago
Read 2 more answers
If launched at the right speed, what could eventually happen to objects launched from Newton's theoretical cannon on the top of
Nadusha1986 [10]
If the speed is higher than the orbital velocity, but not high enough to leave Earth altogether (lower than the escape velocity), it will continue revolving around Earth along an elliptical orbit. (D) for example horizontal speed of 7,300 to approximately 10,000 m/s for Earth.
4 0
3 years ago
How are scientific theories different than laws or hypotheses?
Nina [5.8K]

Answer:The answer is A

Explanation:

3 0
3 years ago
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A fast moving vehicle travelling at a speed of 25.4 m/s comes up behind another vehicle which is
ale4655 [162]

Answer:

     a = 6.1 m / s²

Explanation:

For this kinematics exercise, to solve the exercise we must set a reference system, we place it in the initial position of the fastest vehicle

Let's find the relative initial velocity of the two vehicles

          v₀ = v₀₂ - v₀₁

          v₀ = 25.4 - 13.6

          v₀ = 11.8 m / s

 

the fastest vehicle

          x = v₀ t + ½ a t²

The faster vehicle has an initial speed relative to the slower vehicle, therefore it is as if the slower vehicle were stopped, so the distance that must be traveled in a fast vehicle to reach this position is

          x = 11.4 m

         

let's use the expression

           v² = v₀² - 2 a x

how the vehicle stops v = 0

          a = v₀² / 2x

          a = \frac{11.8^2}{2 \ 11.4}

          a = 6.1 m / s²

this velocity is directed to the left

8 0
3 years ago
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