The capacitance of two square parallel plates will be 1.777 farads.
<h3>What is the capacitance of two parallel plates?</h3>
The body's capacity to hold electric charge is constrained by capacitance. There is a capacitance for each capacitor. Two metallic sheets of area A, spaced by d, make up the standard parallel-plate capacitor.
The parallel plate capacitor formula is given by:
C = ε Ad
Two square parallel plates 6.7 cm on a side are separated by 1.8 mm of paraffin. The dielectric constant of paraffin is 2.2. Then the capacitance of two square parallel plates will be given as,
C = ε Ad
C = 2.2 x 0.67 x 0.67 x 1.8
C = 1.777 farad
Two parallel square plates will have a capacitance of 1.777 farads.
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Yes the winds are moving in a straight line
Answer:
Tension in the cable is T = 16653.32 N
Explanation:
Give data:
Cross section Area A = 1.3 m^2
Drag coefficient CD = 1.2
Velocity V = 4.3 m/s
Angle made by cable with horizontal =30 degree
Density 
Drag force FD is given as
Drag force = 14422.2 N acting opposite to the motion
As cable made angle of 30 degree with horizontal thus horizontal component is take into action to calculate drag force
TCos30 = F_D
T = 16653.32 N
Answer:
0.09 m/s²
Explanation:
Acceleration: This can be defined as the rate of change of velocity.
The S.I unit of acceleration is m/s².
From the question, expression for acceleration is given as
F' = ma
Using Pythagoras Theory,
√(F₁²+F₂²) = ma................... Equation 1
Where F₁ = Force of the First person on the boulder, F₂ = Force of the Second person on the boulder, F' = resultant force acting on the boulder, m = mass of the boulder, a = acceleration of the boulder.
make a the subject of the equation
a = √(F₁²+F₂²) /m................ Equation 2
Given: m = 825 kg, F₁ = 64 N, F₂ = 38 N,
Substitute into equation 2
a = [√(64²+38²)]/825
a = {√(5540)}/825
a = 74.43/825
a = 0.09 m/s²
5.678 * 10^10 is the answer
