The answer is B. The chlorine has 7 electrons at the outer shell. So it will gain one electron to become stable when forms a chloride ion. And the gained electron will stay at the outer shell. So the radius becomes larger.
When a radioactive isotope releases an alpha particle, the atomic number of the atom is decreased by four.
So, the correct answer is B.
Hope this helps,
Davinia.
Subtractive colors mixing with all three primaries will result in black.
<h3>How are the 3 primary subtractive colors combined?</h3>
Adding all three subtractive primary color filters together will absorb all the colors of the white light spectrum as appeared below. Each filter (or pigment) absorbs its harmonizing color and transmits (diffusely reflects) the others.
Primary colors union of these three results in white. The subtractive primary colors are related to the subtraction of light: cyan, magenta, and yellow, the colors used in four-color printing, the union of these results in black.
So we can conclude that the usually used subtractive primary colors are cyan, magenta, and yellow, and if you overlap all three in a successful equal mixture.
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B) The light source can be seen from the penumbra.
The value of Kb of the unknown amine is 3.22 x 10^-4.
Weak electrolytes:
The compound which do not dissociate completely when added to the aqueous solution are called weak electrolytes. The electrolyte and its ions exists in equilibrium. In case of weak base, the equilibrium constant is expressed as Kb.
Calculations:
Step 1:
The percentage of amine ionized at equilibrium is 2.2%.
NH3 + H2O ------> NH4+ + OH-
The concentration of conjugate acid at equilibrium is calculated as:
2.2 = (x/0.65) x 100
x = 0.0143 M
Step 2:
The equilibrium constant (Kb) is calculated as:
Kb = x^2/0.65 - x
= (0.0143)^2/(0.65 - x)
= 3.22 x 10^-4
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