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3 years ago

How can both the pitcher and the glass contain the same volume of iced tea?

Chemistry

1 answer:

erma4kov [3.2K]3 years ago

7 0

Answer: $6,600 $\alpha \sqrt[n]{x} \lim_{n \to \infty} a_n$

Explanation:

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What is a REAL LIFE example of passive transport? Please answer asap!

inn [45]

Well, am not sure but..

teleportation , or dream journey or mind waves transportation

4 0

3 years ago

Which compound is more soluble in an acidic solution than in a neutral solution? agcl hgbr2 baco3 pbi2?

Alisiya [41]

Answer is: BaCO₃ (barium carbonate).
barium carbonate is white powder with low solubility in water, but good solubility in acids (with the exception of sulfuric acid), because it forms solunle salts and carbonic acid (decomposes on carbon(IV) oxide and water).
For example if we add hydrochloric acid in barium carbonate:
BaCO₃(s) + 2HCl(aq) → BaCl₂(aq) + H₂CO₃(aq).

7 0

3 years ago

What would happen if N2 were added to N2(g) + O2(g) = 2NO(9) at

DerKrebs [107]

Balanced chemical equation is :

$N_2(g)+O_2(g)-->2NO(g)$

It is given that the equation is in equilibrium.

We need to find what will happen if we add more $N_2$ is added .

By Le Chatelier's principle :

Changing the concentration of a chemical will shift the equilibrium to the side that would counter that change in concentration.

It means production of the side where content is added will decrease and concentration on other side will increase .

So , more NO would form .

Therefore, option B. is correct.

Hence, this is the required solution.

4 0

3 years ago

How many particles are there in 3 moles of Ag?

lutik1710 [3]

Answer:

6.022×1023 individual items of that something. You have 3 moles, so there are 3×6.022×1023 oxygen molecules

Explanation:

6.022×1023 individual items of that something. You have 3 moles, so there are 3×6.022×1023 oxygen molecules

4 0

2 years ago

A long (i.e., L >> D) stainless steel rod 6.4 mm in diameter is initially at a uniform temperature of 25°C and is suddenly

sp2606 [1]

Answer:

68.4 seconds

Explanation:

Assume that the temperature of the stainless steel rod will reach 120 C in t seconds. According to lumped – capacity analysis use the following expression to determine the value of t

T- T∞/T₀ – T∞ = e^-(hA/ρcV)t, where T is the required temperature, T∞ is the surface temperature, T₀ is initial temperature of the rod, h is the convection heat transfer coefficient, A is surface are, ρ is density of stainless steel, c is specific head and V is the volume of the rod.

Area of rod = π x d x L and Volume of rod is (π/4) x d² L

T - T∞/T₀ – T∞ = e^-(h x π x d x L/ρc(π/4 x d² x L))t

T - T∞/T₀ – T∞ = e^-(4h/(ρ x c x d))t, d is the radius of the log and L is the length of rod

The value of c and ρ for stainless steel can be obtained from the table of properties of metals

Substitute 120 C for T, 150 C for T∞, 25 C for T₀, 7817 kg/m³ for ρ, 460 J/kg.C for c, 6.4 x 10⁻³ m for d, 120 W/m².C for h in the above equation

T - T∞/T₀ – T∞ = e^-(4h/ρ x c x d))t

120 – 150/25 – 150 = e ^ -(4 x 120/7817 x 460 x 6.4 x 10⁻³)t

0.24 = e^-0.02086t

Take natural log on both sides

㏑0.24 = -0.02086t

T = 68.4 seconds

Thus, the temperature of the stainless steel will reach 120 C in 68.4s

5 0

3 years ago