Answer:
v_f = -25.9 m/s
Explanation:
- The complete question is as follows:
" Assume that a pitcher throws a baseball so that it travels in a straight line parallel to the ground. The batter then hits the ball so it goes directly back to the pitcher along the same straight line. Define the direction the pitcher originally throws the ball as the +x direction.
Now assume that the pitcher in Part D throws a 0.145-kg baseball parallel to the ground with a speed of 32 m/s in the +x direction. The batter then hits the ball so it goes directly back to the pitcher along the same straight line. What is the ball's velocity just after leaving the bat if the bat applies an impulse of −8.4N⋅s to the baseball?"
Given:
- mass of baseball m = 0.145 kg
- Speed before impact v_i = 32 m/s
- Speed after impact v_f
- Impulse applied by the bat I = - 8.4Ns
Find:
What is the ball's velocity just after leaving the bat
Solution:
- Impulse is the change in linear momentum of the ball according to Newton's second law of motion:
I = m* ( v_f - v_i )
- Taking the + from pitcher to batsman and - from batsman to pitcher.
- Plug in the values:
-8.4 = 0.145* ( v_f - (32) )
v_f = -57.93103 + 32
v_f = -25.9 m/s
Explanation:
Weight=force=300N
height=2m
time=6seconds
power=?
now,
power (p)=f×h÷t
power=300×2÷6
power=100w
therefore,A man develops 100 watt power in 6 seconds.
Answer: B. It demonstrates a behavior or particles.
Explanation: I took the test and got it right
It is b. sodium because it is in group 1
Answer:
The horizontal and vertical distances are x = 210 m and y = -240.35 m, respectively.
Explanation:
Using the equation of the displacement in the x-direction, we have:
(let's recall we have a constant velocity in this direction)
Where:
- v(ix) is the initil velocity in the x direction (v(ix) = 30 m/s)
- t is the time (t = 7 s)
Now, we need to use the equation of the displacement in the y-direction to find the vertical distance. Here we have an acceleration (g)
Where:
- v(iy) is the initial velocity at the y-direction. In this case, it will be 0
- t is the time
- g is the acceleration of gravity (g=9.81 m/s²)
Then, the vertical position at 7 s is:
Therefore, the horizontal and vertical distances are x = 210 m and y = -240.35 m, respectively. The minus sign means the <u>negative value in the y-direction.</u>
I hope it helps you!
