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andrew-mc [135]
3 years ago
9

An electron in a region where there is an electric field experiences a force of magnitude 3.5 10-16 n. what is the magnitude of

the electric field at the location of the electron?
Physics
1 answer:
natima [27]3 years ago
8 0
<span>The force that an object feels in an electric field is the magnitude of the electric field E times the charge on the object Q. We know that the magnitude of the charge of an electron is 1.6 x 10^{-19} C F = E x Q E = F / Q E = (3.5 x 10^{-16} N) / (1.6 x 10^{-19} C) E = 2.19 x 10^3 N/C The magnitude of the electric field at the location of the electron is 2.19 x 10^3 N/C</span>
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Cindy saw her mother heating a wet pan on the stove. As the pan got hotter, the water on the outside began to dry. Why?
dlinn [17]

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4 0
3 years ago
Listed following is a set of statements describing individual stars or characteristics of stars. Match these to the appropriate
Oksana_A [137]

Answer:

Red giant or super giant → very cool but very luminous

                                      → found in the upper right of the H-R diagram.

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                        → Sun, for example

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Explanation:

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6 0
3 years ago
In a charging process, 4 × 1013 electrons are removed from one small metal sphere and placed on a second identical sphere. Initi
Alina [70]

Answer:

The distance between the two spheres is 914.41 X 10³ m

Explanation:

Given;

4 X 10¹³ electrons, and its equivalent in coulomb's is calculated as follows;

1 e = 1.602 X 10⁻¹⁹ C

4 X 10¹³ e = 4 X 10¹³ X 1.602 X 10⁻¹⁹ C = 6.408 X 10⁻⁶ C

V = Ed

where;

V is the electrical potential energy between two spheres, J

E is the electric field potential between the two spheres N/C

d is the distance between two charged bodies, m

V = \frac{K*q}{d^2}*d = \frac{K*q}{d}

d = \frac{K*q}{V}

where;

K is coulomb's constant = 8.99 X 10⁹ Nm²/C²

d = (8.99 X 10⁹ X 6.408 X 10⁻⁶)/0.063

d = 914.41 X 10³ m

Therefore, the distance between the two spheres is 914.41 X 10³ m

3 0
4 years ago
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