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zlopas [31]
3 years ago
14

WILL MARK BRAINLIEST!!!

Physics
1 answer:
Neporo4naja [7]3 years ago
4 0
The floating of ice helps keep the ocean warm because it keeps the ice at the top of the ocean in certain places. But it also helps aquatic life keep in there Necessary environmental conditions.
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1. A densidade do nitrogênio nas condições normais de temperatura e pressão é igual a 1,24507 kg/m³. Qual a massa de 200 cm³ de
Levart [38]

Answer:

5.49×10⁻⁴ lbm

Explanation:

Convert volume to m³.

V = (200 cm³) (1 m / 100 cm)³ = 0.0002 m³

Find mass in kg.

m = ρV

m = (1.24507 kg/m³) (0.0002 m³)

m = 0.000249 kg

Convert mass to lbm.

m = (0.000249 kg) (2.205 lbm/kg)

m = 0.000549 lbm

m = 5.49×10⁻⁴ lbm

3 0
3 years ago
A steel pot has a bottom with a cross sectional area of .1m2 and has a thickness of 1cm. The pot is filled with boiling water an
jenyasd209 [6]

Answer:

840000 J/min

Explanation:

Area = A = 0.1 m²

Bottom of pot temperature = 200 °C

Thermal conductivity = k = 14 J/sm°C

Thickness = L = 1 cm = 0.01 m

Temperature of boiling water = 100 °C

From the law of heat conduction

Q = kAΔT/L

⇒ Q = 14×0.1×(200-100)/0.01

⇒ Q = 14000 J/s

Converting to J/minute

Q = 14000×60 = 840000 J/min

∴ Heat being conducted through the pot is 840000 J/min

3 0
3 years ago
True or False: The rock cycle is a slow process.
IrinaK [193]
<span>The rock cycle is a slow process is true </span>
8 0
3 years ago
Read 2 more answers
Which would hold more water- a teaspoon (tsp) or a milliliter?
ki77a [65]
A tsp

1 milliliter equals 0.202. US teaspoons. boi did that help
4 0
3 years ago
Read 2 more answers
A straight wire in a magnetic field experiences a force of 0.017 N when the current in the wire is 1.1 A. The current in the wir
mel-nik [20]

Answer:

The new current in the straight wire is 4.98 A

Explanation:

Given;

initial magnetic force on the wire, F₁ = 0.017 N

initial current flowing on the straight wire, I₁ = 1.1 A

When the current in the wire is changed,

new magnetic force on the wire, F₂ =  0.077 N

the new current in the wire, I₂ = ?

Applying equation of magnetic force on conductor;

F₁ = I₁BLsinθ

F₂ = I₂BLsinθ

BLsinθ  = F₁/I₁ = F₂/I₂

I₂ = (F₂I₁)/F₁

I₂ = (0.077 x 1.1) / 0.017

I₂ = 4.98 A

Therefore, the new current in the straight wire is 4.98 A

3 0
3 years ago
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