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lara31 [8.8K]
3 years ago
7

How many different 3d states does the hydrogen atom have?

Chemistry
1 answer:
Taya2010 [7]3 years ago
6 0
An electron in a hydrogen atom would have 10 states for a 3d orbital, like any other element.

n = 3, l = 2, in one of ml = 2, 1, 0, -1, -2 each with ms = -½ or +½ or a total of 10 possible states.

None of these are a ground state of an electron in the hydrogen atom.

Enjoy :)
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The wastewater solution from a factory containing high levels of salts needs to be diluted before it can be released into the en
Vesna [10]

Answer:

3.5 atm

Explanation:

As stated in the question pressure is required to counteract the natural tendency  for water to dilute the more concentrated solution. The difference in concentrations will give us the answer using the osmotic pressure equation.

π = ( n/v)  RT where n/v is the molarity (mol/L), R is the gas constant and T is the temperature.

The difference in osmotic pressure of the solutions is:

Δπ = Δ c RT where c is the difference in molar concentrations.

pressure required = Δπ = (0.190 - 0.048) M x 0.821 Latm/Kmol x 298 K

= 3.47 atm

3 0
3 years ago
A compound contains 40.0% carbon, 6.7% hydrogen, and 53.3% oxygen (by mass). calculate the empirical formula.
Eva8 [605]
C:H:O = 40/12 : 6,7/1 : 53,3/16 = 3,33 : 6,7 : 3,33 ≈ 1 : 2 : 1

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3 0
3 years ago
Determine the correct name for the compound MG3N2
SSSSS [86.1K]
Mg3N2 is Magnesium nitride
5 0
2 years ago
How are all atoms alike
Andru [333]

Because all atoms are made from the same particles which are protons, neutrons, and electrons.

Hope this helped!!!

8 0
2 years ago
I’m struggling with dimensional analysis in chemistry! Will someone please help me with .74 Kcal/min to cal/sec ? Explain and gi
valina [46]

Answer:

            12.33 cal/sec

Explanation:

As we know,

                          1 Kcal  =  1000 cal

So,

                     0.74 Kcal  =  X cal

Solving for X,

                      X =  (0.74 Kcal × 1000 cal) ÷ 1 Kcal

                      X =  740 cal

Also we know that,

                      1 Minute  =  60 Seconds

Therefore, in order to derive cal/sec unit replace 0.74 Kcal by 740 cal and 1 min by 60 sec in given unit as,

                                       = 740 cal / 60 sec

                                       = 12.33 cal/sec

3 0
3 years ago
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