Answer:
2123.55 $/hr
Explanation:
Given parameters are:
KV
L = 143 km
I = 500 A
So, we will find the voltage potential provided for the city as:
kV
kV
Then, we will find dissipated power because of the resistive loss on the transmission line as:
W
Since the charge of plant is not given for electric energy, let's assume it randomly as
Then, we will find the price of energy transmitted to the city as:
$/hr
To calculate money per hour saved by increasing the electric potential of the power plant:
Finally,
$/hr
The amount of money saved per hour = $/hr
Note: For different value of the price of energy, it just can be substituted in the equations above, and proper result can be found accordingly.
Answer:
x = 1.04866
Explanation:
Force can be defined from power energy by the expressions
F =
in this case we are the expression of the potential energy
U =
let's find the derivative
dU / dx = 2.6 ( ) - 4.3 ()
dU / dx =
we substitute
F = + \frac{20.8}{ x^{9} } - \frac{17.2 }{ x^{5} }
at the equilibrium point the force is zero, so
20.8 / 17.2 = x⁴
x⁴ = 1.2093
x =
x = 1.04866
The coefficient of friction between the Tyre and the ground is 0.11
<u>Explanation:</u>
Given:
Radius of the track (r)=125 m.
Speed with which the car travels (v) =42 km/hr
=11.67 m/s
To Find:
Coefficient of friction between the Tyre and the ground.
Formula to be used:
We know that,Frictional force is equal to centripetal force
Frictional force=μmg
therefore 1.08 m=μmg
Cancelling "m" on both sides we get,
μ=1.08/g=1.08/9.8
=0.11
Thus the coefficient of friction between the Tyre and the ground is 0.11
Three Types of Solutions of a System of Linear Equations. There are three possible outcomes for a system of linear equations: one unique solution, infinitely many solutions, and no solution. This video shows an example of each type of outcome.
Answer:
Explanation:
Here h=36m, a=g=10m/s, u=0
Use s=ut+(1/2)at^2
36=0*t+(10t^2)/2
time=2.68 sec
As from the formula of final velovity, v=(2gh)^1/2
v=(2*10*36)^1/2
v=(720)^1/2
v=26.83………This is the final velocity