Answer:
The pressure difference will increase by the factor of 1.75
Explanation:
For constant flow rate, coefficient of viscosity, length of the vessel and the pressure difference is inversely proportional to the fourth power of the radius of the blood vessel
Apply the principle of Poiseuille’s law.
Q = (P2 - P1)/R
Pls check the attached file for step by step solution of the question. It is submitted in this way as typing the equation may not be explanatory.
Answer:
a
The orbital speed is
b
The escape velocity of the rocket is
Explanation:
Generally angular velocity is mathematically represented as
Where T is the period which is given as 1.6 days =
Substituting the value
At the point when the rocket is on a circular orbit
The gravitational force = centripetal force and this can be mathematically represented as
Where G is the universal gravitational constant with a value
M is the mass of the earth with a constant value of
r is the distance between earth and circular orbit where the rocke is found
Making r the subject
The orbital speed is represented mathematically as
Substituting value
The escape velocity is mathematically represented as
Substituting values
Answer:
The momentum is 1.94 kg m/s.
Explanation:
To solve this problem we equate the potential energy of the spring with the kinetic energy of the ball.
The potential energy of the compressed spring is given by
,
where is the length of compression and is the spring constant.
And the kinetic energy of the ball is
When the spring is released all of the potential energy of the spring goes into the kinetic energy of the ball; therefore,
solving for we get:
And since momentum of the ball is ,
Putting in numbers we get:
Answer:
13 530 482
Explanation:
H2 + I2 ------> 2HI
start (mol) 0.3785 0.3818 0
change (mol) -0.3534 -0.3534 +0.7067
equilibrium (mol) 0.0251 0.0284 0.7067
concentra (mol/L) 0.0068 0.0077 0.1926
Answer:
16∠45° Ω
Explanation:
Applying,
Z = V/I................... Equation 1
Where Z = Impedance, V = Voltage output, I = current input.
Given: V = 120cos(10t+75°), = 120∠75°, I = 7.5cos(10t+30) = 7.5∠30°
Substitute these values into equation 1
Z = 120cos(10t+75°)/7.5cos(10t+30)
Z = 120∠75°/ 7.5∠30°
Z = 16∠(75°-30)
Z = 16∠45° Ω
Hence the impedance of the linear network is 16∠45° Ω