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gizmo_the_mogwai [7]
3 years ago
13

An example of a characteristic property of a mineral is

Physics
1 answer:
rodikova [14]3 years ago
4 0
I will give you more than one , hardness,luster,color,streak,cleavage,fracture.
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Order from biggest to smallest?<br> Milky Way, universe, planets, clusters, and stars
Zinaida [17]
Hello,

The answer is "universe, Milky Way, clusters, stars, planets".

Reason:

The universe would be the biggest because it has all the galaxy's, starts, clusters, and planets into one. Then it would be Milky Way because this is a galaxy that contains: stars, planets, and clusters. Then it would be clusters because that contains stars, or planets in one group. Then be stars because stars are bigger than planets. Then it would be planets. Therefore the order should go like this: <span>Milky Way, universe, planets, clusters, and stars.

If you need anymore help feel free to ask me!

Hope this helps!

~Nonportrit</span>
5 0
3 years ago
Read 2 more answers
A jogger moves from a position x =
vlada-n [284]

Answer:

3 m/s

Explanation:

We'll begin by calculating the change in displacement of the jogger. This can be obtained as follow:

Initial displacement (d₁) = 4 m

Final displacement (d₂) = 16 m

Change in displacement (Δd) =?

Δd = d₂ – d₁

Δd = 16 – 4

Δd = 12 m

Finally, we shall determine the determine the average velocity. This can be obtained as follow:

Change in displacement (Δd) = 12 m

Time (t) = 4 s

Velocity (v) =?

v = Δd / t

v = 12 / 4

v = 3 m/s

Thus, the average velocity of the jogger is 3 m/s

5 0
3 years ago
Can someone complete this assignment will give brainliest!<br> The assignment is attached
Musya8 [376]
... I can’t see the attached assignment that you put on here.
3 0
3 years ago
Two of the three tuning forks have known frequencies. When a 610 Hz fork and the unknown fork are struck together, four beats pe
RUDIKE [14]

-- In combination with 610 Hz, the beat frequency is 4 Hz.

So the unknown frequency is either (610+4) = 614 Hz
or else (610-4) = 606 Hz.

In combination with 605 Hz, the beat frequency will be
either (614-605) = 9 Hz or else (606-605) = 1 Hz.

-- In actuality, when combined with the 605 Hz, the beat
frequency is too high to count accurately.  That must be
the 9 Hz rather than the 1 Hz.

So the unknown is (605+9) = 614 Hz.
 
6 0
3 years ago
Can anyone help me plz I m confused with this last question?
Gemiola [76]

Answer:

764728497693575177015915715716245378tr7138

Explanation:

8 0
3 years ago
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