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3 years ago

Can we use momentum to see how fast the earth is going?

Physics

1 answer:

Kisachek [45]3 years ago

6 0

Yes, if we know the Earth's mass

Explanation:

The momentum of an object is a vector quantity given by the equation

$p=mv$

where

m is the mass of the object

v is its velocity

In this case, we are asked if we can find the velocity of the Earth by starting from its momentum. Indeed, we can. In fact, we can rewrite the equation above as

$v=\frac{p}{m}$

Therefore, if we know the momentum of the Earth (p) and we know its mass as well (m), we can solve the formula to find the Earth's velocity.

Learn more about momentum:

brainly.com/question/7973509

brainly.com/question/6573742

brainly.com/question/2370982

brainly.com/question/9484203

#LearnwithBrainly

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Norma-Jean [14]

Given: distance 1 d₁ = 40 m; distance 2 d₂ = 3.8 m g = -9.8 m/s²

Initial Velocity Vi = 0 Final Velocity of stone 2 is unknown = ?

Total distance dₓ = d₁ - d₂ = 40 m - 3.8 m = 36.2 m

Formula: a = Vf² - Vi²/2d derive for Final Velocity Vf

acceleration is now due to gravity, therefore a = g

Vf = √2gd Vf = √2(9.8 m/s²)(36.2 m)

Vf = 26.64 m/s

Reason: The second stone will still start from rest.

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3 years ago

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3 years ago

A car of mass m accelerates from rest along a level straight track, not at constant acceleration but with constant engine power,

lisabon 2012 [21]

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3 years ago

On an ice skating rink, a girl of mass 50 kg stands stationary, face to face with a boy of mass 80 kg. The children push off of

sasho [114]

The velocity of the girl is -4.8 m/s.

Using the principle of conservation of linear momentum, The total momentum of bodies before and after collision is constant. Since the two objects are stationary, the initial momentum of each body is zero.

Thus;

0 = (80 × 3) + (50 × v)

0 = 240 + 50 v

-240 = 50 v

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Note that the negative sign shows that the velocity of the girl is in opposite direction that that of the girl.

Learn more about momentum: brainly.com/question/904448

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3 years ago

A constant force of 12N is applied for 3.0s to a body initially at rest. The final velocity of the body is 6.0ms–1. What is the

sp2606 [1]

From the question,
$u = 0m {s}^{ - 1}$
$v = 6m {s}^{ - 1}$

$t = 3s$
$F=12N$

Using Impulse, the product of the constant force, F and time t equals the product of the mass of the body and change in velocity.

$Ft =m(v-u)$

$12(3.0)=m(6.0- \: 0)$
This implies that

$36.0 = 6m$
$m = \frac{36.0}{6.0}$
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You can also use the equation of linear motion,
$v = u + at$
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$6 = 3a$
$a = \frac{6}{3}$

$a = 2 {ms}^{ - 2}$
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$F=ma$
$12 = m(2)$
$12 = 2m$
$\frac{12}{2} = m$
$\therefore \: m = 6kg$

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3 years ago