I'm pretty sure number 48 is C. Hope this helped :)
<u>Answer:</u> The correct answer is Option d.
<u>Explanation:</u>
Nuclear fission reaction is defined as the reaction in which 1 heavier nuclei splits into two or more smaller nuclei.
As, nuclear fission reactors require a large amount of energy to split the nucleus, hence it is bombarded with a particle in order to star the reaction.
In a nuclear reaction, a large fissile atomic nucleus like Uranium-235
or Plutonium-239
when absorbs a neutron, it undergoes nuclear fission reaction.
Hence, in the given options, uranium-235 is absorbing a neutron. Therefore, the correct answer is Option d.
Answer:
a) The value of the
is 0.52.
b)Concentration of all species when equilibrium reestablishes:
![[CO_2] = 0.4748 M](https://tex.z-dn.net/?f=%5BCO_2%5D%20%3D%200.4748%20M)
![[H_2] = 0.0198 M](https://tex.z-dn.net/?f=%5BH_2%5D%20%3D%200.0198%20M)
![[CO] = 0.0752 M](https://tex.z-dn.net/?f=%20%5BCO%5D%20%3D%200.0752%20M)
![[H_2O] =0.0652 M](https://tex.z-dn.net/?f=%5BH_2O%5D%20%3D0.0652%20M)
Explanation:
a) 
Equilibrium concentration of species :
![[CO] = 0.050 M, [H_2] = 0.045 M, [CO_2] = 0.086 M, and [H_2O] = 0.040 M](https://tex.z-dn.net/?f=%5BCO%5D%20%3D%200.050%20M%2C%20%5BH_2%5D%20%3D%200.045%20M%2C%20%5BCO_2%5D%20%3D%200.086%20M%2C%20and%20%5BH_2O%5D%20%3D%200.040%20M)
The expression of equilibrium constant is given as :
![\K_c=\frac{[CO][H_2O]}{[CO_2][H_2]}](https://tex.z-dn.net/?f=%5CK_c%3D%5Cfrac%7B%5BCO%5D%5BH_2O%5D%7D%7B%5BCO_2%5D%5BH_2%5D%7D)

b)

Initially:
0.50 M 0.045 M 0.050 M 0.040 M
At equilibrium ;
(0.50-x) M (0.045-x) M (0.050+x) M (0.040+x) M
![K_c=\frac{[CO][H_2O]}{[CO_2][H_2]}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BCO%5D%5BH_2O%5D%7D%7B%5BCO_2%5D%5BH_2%5D%7D)

Solving fro x;
x = 0.0252
Concentration of all species when equilibrium reestablishes:
![[CO_2] = (0.50-x) M=(0.50-0.0252)M = 0.4748 M](https://tex.z-dn.net/?f=%5BCO_2%5D%20%3D%20%280.50-x%29%20M%3D%280.50-0.0252%29M%20%3D%200.4748%20M)
![[H_2] = (0.045-x) M= (0.045-0.0252) M=0.0198 M](https://tex.z-dn.net/?f=%5BH_2%5D%20%3D%20%280.045-x%29%20M%3D%20%280.045-0.0252%29%20M%3D0.0198%20M)
![[CO] = (0.050+x) M=(0.050+0.0252)M = 0.0752 M](https://tex.z-dn.net/?f=%20%5BCO%5D%20%3D%20%280.050%2Bx%29%20M%3D%280.050%2B0.0252%29M%20%3D%200.0752%20M)
![[H_2O] = (0.040+x) M=(0.040+0.0252) M=0.0652 M](https://tex.z-dn.net/?f=%5BH_2O%5D%20%3D%20%280.040%2Bx%29%20M%3D%280.040%2B0.0252%29%20M%3D0.0652%20M)