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damaskus [11]
3 years ago
8

Water has many exceptional and useful properties. which is the rarest property

Chemistry
1 answer:
Tasya [4]3 years ago
5 0
Solid water is less dense than liquid water.

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List two processes from which it may be concluded that the particles of a gas move continuously.
ziro4ka [17]

Answer:

The two processes maybe:

  • One process can be the spread of smell of perfume . Tge particles of perfume mic in the air and reaches every corner of tge room because they are moving

  • Second can be the smell of food that reaches us in seconds . This case too tells that the aroma of the food particles gets intermixed and come to us .
5 0
4 years ago
Help me out please due tomorrow
skelet666 [1.2K]
I'm pretty sure number 48 is C. Hope this helped :)
6 0
3 years ago
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URGENT!!!!!!!!Which reaction takes place in a nuclear fission reactor?
ivolga24 [154]

<u>Answer:</u> The correct answer is Option d.

<u>Explanation:</u>

Nuclear fission reaction is defined as the reaction in which 1 heavier nuclei splits into two or more smaller nuclei.

As, nuclear fission reactors require a large amount of energy to split the nucleus, hence it is bombarded with a particle in order to star the reaction.

In a nuclear reaction, a large fissile atomic nucleus like Uranium-235 (_{92}^{235}\textrm{U}) or Plutonium-239 (_{94}^{239}\textrm{Pu}) when absorbs a neutron, it undergoes nuclear fission reaction.

Hence, in the given options, uranium-235 is absorbing a neutron. Therefore, the correct answer is Option d.

6 0
3 years ago
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Which of the different components of smog depicted in the graph are most likely released from automobile exhaust?
CaHeK987 [17]

Answer:

B, B and C

Explanation:

6 0
3 years ago
Consider the following equilibrium process at 686°C. CO2(g) + H2(g) equilibrium reaction arrow CO(g) + H2O(g) The equilibrium co
coldgirl [10]

Answer:

a) The value of the K_c is 0.52.

b)Concentration of all species when equilibrium reestablishes:

[CO_2] = 0.4748 M

[H_2] = 0.0198 M

[CO] = 0.0752 M

[H_2O] =0.0652 M

Explanation:

a)  CO_2(g) + H_2(g)\rightleftharpoons CO(g) + H_2O(g)

Equilibrium concentration of species :

[CO] = 0.050 M, [H_2] = 0.045 M, [CO_2] = 0.086 M, and [H_2O] = 0.040 M

The expression of equilibrium constant is given as :

\K_c=\frac{[CO][H_2O]}{[CO_2][H_2]}

=\frac{0.050 M\times 0.040 M}{0.086 M\times 0.045 M}=0.517\approx 0.52 M

b)

CO_2(g) + H_2(g)\rightleftharpoons CO(g) + H_2O(g)

Initially:

0.50 M    0.045 M      0.050 M   0.040 M

At equilibrium ;

(0.50-x) M    (0.045-x) M      (0.050+x) M   (0.040+x) M

K_c=\frac{[CO][H_2O]}{[CO_2][H_2]}

0.52=\frac{(0.050+x) M\times (0.040+x) M}{(0.50-x) M\times (0.045-x) M}

Solving fro x;

x = 0.0252

Concentration of all species when equilibrium reestablishes:

[CO_2] = (0.50-x) M=(0.50-0.0252)M = 0.4748 M

[H_2] = (0.045-x) M= (0.045-0.0252) M=0.0198 M

[CO] = (0.050+x) M=(0.050+0.0252)M = 0.0752 M

[H_2O] = (0.040+x) M=(0.040+0.0252) M=0.0652 M

8 0
4 years ago
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