The force result in stretching the spring 10.0 centimeters is 2.5N.
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What is Hooke's law?</h3>
If a spring is stretched from its equilibrium position, then a force with magnitude proportional to the increase in length from the equilibrium length is pulling each end.
F = kx
where k is the proportionality constant called the spring constant or force constant.
Up to a point, the elongation of a spring is directly proportional to the force applied to it. Once you extend the spring more than 10.0 centimeters, however, it no longer follows that simple linear rule.
Let the spring constant be very low 0.04N/m
The force applied is
F = 10 cm / 0.04
F = 0.1 m / 0.04
F = 2.5 N
Thus, the force result in stretching the spring 10cm is 2.5 N.
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Answer
given,
V = 2 L
the left is an ideal gas at P = 100 k Pa and T = 500 K
mass is constant
Pressure is same because it's not changing due to process
m = 1.39 x 10⁻³ Kg
The pain was triggered by the Nervous System
Answer:
A kg of cotton is heavier.
Explanation:
Because in air, cotton gets upthrust that's why weighing machine gives less weight than its actually have.
for eg: If cotton has 800g weight, the machine shows a kg(1kg) when measure in air due to upthrust.
I hope this will be helpful for you.
