Complete the equation for the ionization of water by drawing the conjugate acid and conjugate base. Include lone pairs of electr
ons. Two water molecules react to form the conjugate acid which has a plus 1 charge, and the conjugate base, which has a minus one charge. Each water molecule consists of a central oxygen atom bonded to two hydrogen atoms. There are two lone pairs on the oxygen atom.
2 answers:
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Answer:
Final temperature: 659.8ºC
Expansion work: 3*75=225 kJ
Internal energy change: 275 kJ
Explanation:
First, considering both initial and final states, write the energy balance:
Q is the only variable known. To determine the work, it is possible to consider the reversible process; the work done on a expansion reversible process may be calculated as:
The pressure is constant, so: (There is a multiplication by 100 due to the conversion of bar to kPa)
So, the internal energy change may be calculated from the energy balance (don't forget to multiply by the mass):
On the other hand, due to the low pressure the ideal gas law may be appropriate. The ideal gas law is written for both states:
Subtracting the first from the second:
Isolating :
Assuming that it is water steam, n=0.1666 kmol
ºC