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Tems11 [23]
3 years ago
9

A bomb calorimeter has a heat capacity of 2.47 kJ/K. When a 0.105-g sample of ethylene (C 2H 4) was burned in this calorimeter,

the temperature increased by 2.14 K. Calculate the energy of combustion for one mole of ethylene.
Physics
1 answer:
svetlana [45]3 years ago
7 0

Answer:

Combustion energy for one mole of ethylene  = 1410.51 kJ/mol

Explanation:

Given data

heat capacity of bomb calorimeter = 2.47kJ/K

\Delta T = 2.14 K

molecular weight of C_2H_4 =  2*12.01+1.008*4=28.052

Total energy released after burning 0.105 g sample is = 2.47 *2.14 =5.28 kJ

Combustion energy for one mole of ethylene = \frac{5.28 *28.05}{0.105}

                                                                            = 1410.51 kJ/mol

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