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Elena L [17]
3 years ago
12

Iron man wears an awesome ironsuit.He is flying over high current carrying wire. Will he be affected?

Physics
1 answer:
frozen [14]3 years ago
8 0

Answer:

According to super hero logic , nothing will happen to him.

But according to science , yes he will get current shock but good news is that he wouldn't get elected until he is in contact with the wires.

He may / may not be affected but his suit will be damaged for sure as it is made of metal.

HOPE THIS HLEP AND PLSSSSS MARK AS BRAINLIEST AND THNXX :)

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A ball is thrown upwards at a velocity of 20.2m/s at what time will the ball reach its highest point
Andre45 [30]
Use the equation
vf = vo + a \times t
plug in the variables for the equation. Use 0 for Vf because at the highest point the velocity would be zero. Use -9.8 for acceleration because that is the speed at which gravity pulls down.
0 = 20.2 + ( - 9.8) \times t
your answer would be 2.06122 seconds.
7 0
3 years ago
Describe the role of the teacher and the learner in a natural science and technology classroom​
dem82 [27]
Teacher -> teach the topic
Learner -> learn the topic
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3 years ago
3. Using the F, m, a triangle, calculate the boy's mass. Use the "force
aliya0001 [1]

Answer: 30kg

Explanation:

F = 300N

m = ?

a = 10 m/s/s

m = f/a = 300N/10 m/s/s

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5 0
3 years ago
A pressure that will support a column of Hg to a height of 256 mm would support a column of water to what height? The density of
Paul [167]

Answer:

<em>The height of water in the column = 348.14 cm</em>

Explanation:

<em>Pressure:</em><em>This is defined as the ratio of the force acting normally ( perpendicular) to the area of surface in contact. The S.I unit of  pressure is N/m²</em>

<em>p = Dgh............... Equation 1</em>

<em>Where p = pressure, D = density, g = acceleration due to gravity, h = height.</em>

<em>From the question, the same pressure will support the column of mercury and water.</em>

<em>p₁ = p₂</em>

<em>Where p₁ = pressure of mercury, p₂ = pressure of water</em>

D₁gh₁ = D₂gh₂.................. Equation 2

making h₂ the subject of equation 2

h₂ = D₁gh/D₂g............... Equation 3

Where D₁ and D₂ = Density of mercury and water respectively, h₁ and h₂ = height of mercury and water respectively

Given: D₁ = 13.6 g/cm³, D₂ = 1.00 g/cm³, h₁ = 256 mm = 25.6 cm.

Constant: g = 9.8 m/s²

Substituting these values into Equation 3,

h₂ = (13.6×9.8×25.6)/1×9.8

<em>h₂ = 348.14 cm</em>

<em>The height of water in the column = 348.14 cm</em>

6 0
3 years ago
Susan gently pushes the tip of her finger against the eraser on her pencil and the pencil does not move. Which of the
pochemuha

Answer: D. ➡️⬅️

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6 0
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