The formula we use would be the graham's law. We do as follows:

<span>E_Kr / E_Ne = sqrt ( M_Ne / M_Kr)
</span>
<span>= sqrt ( 20.1797 g/mol / 83.798 g/mol ) </span>
<span>= sqrt (0.24081) </span>
<span>= 0.4907
</span>
Hope this answers the question. Have a nice day.

7 0

3 years ago

Read 2 more answers

If it takes 5 hours to produce 8.0 kg of alcohol, how any days will it take to consume 1000 kg of glucose?

Ipatiy [6.2K]

It takes 21.3 days

<h3>Further explanation</h3>

Given

5 hr = 8 kg Alcohol

Required

Days to consume 1000 kg of glucose

Solution

Alcoholic fermentation⇒ glucose produces ethanol and carbon dioxide,

C₆H₁₂O₆ → 2 C₂H₅OH + 2CO₂

mol ethanol :

$\tt \dfrac{5000~g}{46~g/mol}=108.7~moles$

moles of glucose to produce 108.7 moles ethanol :

$\tt \dfrac{1}{2}\times 108.7=54.35$

54.35 moles = 5 hours

moles of 1000 kg of glucose :

$\tt \dfrac{10^6~g}{180~g/mol}=5555.5~moles$

So for 5555.5 moles, it takes :

$\tt \dfrac{5555.5}{54.35}\times 5~hours=511.085~h=21.3~days$

7 0

3 years ago

What is the formula for triboron silicide?

artcher [175]

Answer:

B₃Si

Explanation:

Let's take break it down. From triboron silicide;

Tri - Three

Triboron - Three boron atoms

Silicide - Silicon (with an -ide suffix)

The formular is given as;

B₃Si

7 0

3 years ago