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2 years ago

Qual a relação e as PROPORÇÕES entre Joules, cal, Cal, e Kcal?

Chemistry

1 answer:

RUDIKE [14]2 years ago

6 0

Answer:

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Explanation:

English Translation

What is the relationship and the PROPORTIONS between Joules, lime, Cal, and Kcal?

Joules is the SI unit of Energy (heat energy).

Calorie, also called lime, is the amount of heat required to raise the temperature of 1 gram of pure water by 1°C or 1 K.

1 calorie = 4.186 J

A thousand calorie is equal to 1 kcal.

Hence,

1 kcal = 1000 calories = 4186 J

In Portugese/Em português

Joules é a unidade SI de energia (energia térmica).

Caloria, também chamada de cal, é a quantidade de calor necessária para elevar a temperatura de 1 grama de água pura em 1°C ou 1 K.

1 caloria = 4,186 J

Mil calorias é igual a 1 kcal.

Portanto,

1 kcal = 1000 calorias = 4186 J

Hope this Helps!!!

Espero que isto ajude

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"acid is responsible for the odor in rancid butter. a solution of 0.25 m butyric acid has a ph of 2.71. what is the ka for"

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Answer:- The Ka for the acid is $1.53*10^-^5$ .

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HA(aq)\rightarrow H^+(aq) + A^-(aq)

Now, we make the ice table for this equation as:

HA(aq)\rightarrow H^+(aq) + A^-(aq)

I 0.25 0 0

C -X +X +X

E (0.25 - X) X X

where, I stands for initial concentration, C stands for change in concentration and E stands for equilibrium concentration.

X is the change in concentration and from ice table it's same as the concentration of hydrogen ion that is calculated from given pH.

$Ka = [H^+][A^-]\frac{1}{HA}$

Where, Ka is the acid ionization constant. Let's plug in the values.

$Ka = \frac{X^2}{0.25-X}$

Let's calculate the value of X first using the equation:

$pH = -log[H^+]$ [/tex]

on taking antilog ob above equation we get:

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$[H^+]$ = 0.00195

So, X = 0.001195

Let's plug in this value of X in the equation:-

$Ka=\frac{(0.00195)^2}{0.25-0.00195}$

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Vladimir79 [104]

Answer:

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Explanation:

1) The solubility of O₂ gas in water:

We cam calculate the solubility of O₂ in water using Henry's law: Cgas = K P,

where, Cgas is the solubility if gas,

K is henry's law constant (K for O₂ at 25 ̊C is 1.3 x 10⁻³ mol/l atm),

P is the partial pressure of O₂ (P = 120 torr / 760 = 0.158 atm).

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2) The effect of decreasing temperature on the solubility O₂ gas in water:

Decreasing the temperature will increase the solubilty of O₂ gas in water.

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Decreasing the temperature will increase the solubility of O₂ gas in water will because the kinetic energy of gas particles will decrease and limit its motion that can not break the intermolecular bonds and increase the solubility of O₂ gas.

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