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svetlana [45]
4 years ago
9

HELPPPPP WILL GIVE BRAINLIEST!!!

Physics
2 answers:
Lady bird [3.3K]4 years ago
7 0

Answer:

3.round object that orbits the Sun but lacks the ability to clear the neighborhood around its orbit.

Explanation:

in 2006 the IAU, said that a dwarf planet is round object that has not cleared the area round a object and that is why Pluto, Ceres, and Eris are dwarf planet.

Vsevolod [243]4 years ago
3 0

Answer:

A dwarf planet is a<u><em> "round object that orbits the Sun but lacks the ability to clear the neighborhood around its orbit." (option 3)</em></u>

Explanation:

A dwarf planet is defined as a celestial body that is characterized by:

  • Being in orbit around the Sun (rotate around this)
  • Its mass is enough for its own gravity to exceed the stiff body strength. In other words: it has a spherical or almost spherical shape determined by hydrostatic equilibrium.
  • It is not a planet's satellite.
  • It has failed to clean the neighborhoods of its orbit. In general, a star reaches a certain level of evolution and incisively influences the surrounding stars, either by attracting them, moving them away or making them revolve around it. This is not the case with dwarf planets, which causes other relatively independent stars to exist around their orbit. In other words, the planet revolves around the Sun accompanied by other celestial bodies that perform the same orbit (it is not gravitationally dominant as it shares its orbital space with other bodies of similar size).

In summary, <u><em>a dwarf planet is a "round object that orbits the Sun but lacks the ability to clear the neighborhood around its orbit." (option 3)</em></u>

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4
alexandr402 [8]

Answer:

Velocity Has vector Quantity

4 0
3 years ago
A 10 kg ball is traveling at the same speed as a 1 kg ball. Compared to the 10 kg ball, the 1 kg ball has
Colt1911 [192]
We can compare the two by their kinetic energies. The kinetic energy is the energy when an object is in motion. It is expressed as the product of the mass of the object and the square of the velocity divided by two. We assume a velocity of 1 m/s for this problem.<span>

KE = mv^2/2
KE1 = 10 (1)^2
KE1 = 10 J

KE2 = 1(1)^2
KE2 = 1 J

Therefore, c</span><span>ompared to the 10 kg ball, the 1 kg ball has lesser kinetic energy.</span>
3 0
3 years ago
What equation/formula would you use to find the distance an object traveled?
Rudik [331]

Answer:

a. distance = s x t

Explanation:

The equation we know for speed is speed = distance/time, shortened to s = d/t

If you want to find the distance, you'd rearrange the formula to make d the subject. To isolate d, multiply by t on both sides (since it's being divided on the right. This leads to

s x t = d, with d isolated on the right side.

Therefore, to find the distance an object travelled you'd use a. distance = s x t

7 0
3 years ago
Read 2 more answers
A 94.0 N grocery cart is pushed 17.6 m along an aisle by a shopper who exerts a constant horizontal force of 42.6 N. The acceler
Vadim26 [7]

Answer:

vf = 12.51 m/s

Explanation:

Newton's second law to the grocery cart:

∑F = m*a Formula (1)

∑F : algebraic sum of the forces in Newton (N)

m : mass s (kg)

a : acceleration  (m/s²)

We define the x-axis in the direction parallel to the movement of the grocery cart  and the y-axis in the direction perpendicular to it.

Forces acting on the grocery cart

W: Weight of the block : In vertical direction  downward

N : Normal force : In vertical direction  upward

F : horizontal force

Calculated of the mas of the grocery cart (m)

W = m*g

m = W/g

W = 94.0 N  , g = 9.81 m/s²

m = 94/9.81

m = 9.58 Kg

Calculated of the acceleration of the grocery cart (a)

∑F = m*a

F = m*a

42.6 = (9.58)*a

a = (42.6) / (9.58)

a = 4.45 m/s²

Kinematics Equation of the grocery cart

Because the grocery cart moves with uniformly accelerated movement we apply the following formula to calculate its final speed :

vf²=v₀²+2*a*d Formula (2)

Where:  

d:displacement  (m)

v₀: initial speed  (m/s)

vf: final speed   (m/s)

a: acceleration (m/s²)

Data:

v₀ = 0

a = 4.45 m/s²

d = 17.6 m

We replace data in the formula (2) :

vf²=v₀²+2*a*d

vf² = 0+2*(4.45)*(17.6)

vf² = 156.64

v_{f} = \sqrt{156.64}

vf = 12.51 m/s

7 0
4 years ago
With the switch open, roughly what must be the resistance of the resistor on the right for the current out of the battery to be
jeyben [28]

Question:

Assumptions

Voltage of battery = 24 V

Resistance on the right,20Ω parallel to 10 Ω resistor

Answer:

For the current out of the battery to be the same as when the switch was opened with the switch closed, the resistance on the resistor on the right must be approximately 20/3 Ω

Explanation:

We note that the switch in the assumption is on the same line as the 20 Ω resistor.

With a voltage of 24 V, and the switch closed, we have;

Total resistance =  \frac{1}{\frac{1}{10} +\frac{1}{20} } = \frac{20}{3} \Omega

Current out of voltage, I  = Voltage/(total resistance)

= 24 ÷ 20/3 = 24 × 3/20 = 18/5 A

Therefore, with the switch opened, we get

Resistance on the right = Initial total resistance =  \frac{20}{3} \Omega

Therefore, with the switch opened, the resistance on the resistor on the right must be approximately equal to the resultant resistance of the two resistances in parallel.

6 0
3 years ago
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