U=RI Ohm's law
then R=U/I
 =120/0.08
 =2250Ω
hope this helps you
        
             
        
        
        
Acceleration is the rate of change of the velocity of an object that is moving. This value is a result of all the forces that is acting on an object which is described by Newton's second law of motion. To determine acceleration, we need to know the initial velocity and the final velocity and the time elapsed. From the given values, we need t o calculate for the initial velocity. We use some kinematic equations. We do as follows:
 x = v0t + at^2/2
60 = v0(6) + a(6)^2/2
60 = 6v0 + 18a          (EQUATION 1)
vf = v0 + at
15 = v0 + a(6)
15 = v0 + 6a             (EQUATION 2)
Solving for v0 and a,
v0 = 5 m/s
a = 1.7 m/s^2
        
             
        
        
        
Answer:
75.36 mph
Explanation:
The distance between the other car and the intersection is,
 
The distance between the police car and the intersection is,
 
 
(Negative sign indicates that he is moving towards the intersection)
Therefore the distance between them is given by,
 
 
The rate of change is,
 
 
Now finding  when
 when  from (1) we have
 from (1) we have
 
 
The officer's radar gun indicates 25 mph pointed at the other car then,  when
 when  from
 from
From (2) we get
 
 
 
 
Hence the speed of the car is 
 
        
             
        
        
        
Answer:
0-4 acceleration comes at 12 m/s where (B) stagnates at 12 m/s and remains for 4 seconds (C) is breaks being activated slowing the car to 6 m/s in 2 seconds and (D) over the course of 4 seconds brings the car to 10 m/s. 
Explanation: