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Nookie1986 [14]
3 years ago
12

Will something that is water soluble dissolve in oil

Chemistry
1 answer:
lawyer [7]3 years ago
4 0
Something like that wouldn't dissolve in oil
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Some common substances and their chemical formulas are listed in the chart.
vesna_86 [32]

Answer:

We heart you don't have all the information you just got some common substances and their chemical formulas are listed in the chart? That we don't have the chart to see which of the substances are elements

Explanation:

sorry about that if you can take a picture of it and repost it I am sure I could answer it for you

8 0
3 years ago
1. What does it mean for a substance to be soluble?​
Anni [7]

Answer:

Solubility is a chemical property referring to the ability for a given substance, the solute, to dissolve in a solvent. It is measured in terms of the maximum amount of solute dissolved in a solvent at equilibrium. ... Certain substances are soluble in all proportions with a given solvent, such as ethanol in water.

Explanation:

3 0
3 years ago
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The results of a classroom group activity performed to test the acidic or basic nature of two substances are shown in the table.
zvonat [6]
Substance a is a base, and substance b is an acid
4 0
3 years ago
Helpppp pleaseee ill give brainliest
Studentka2010 [4]

Answer:

The answers are in the explanation.

Explanation:

The energy required to convert 10g of ice at -10°C to water vapor at 120°C is obtained per stages as follows:

Increasing temperature of ice from -10°C - 0°C:

Q = S*ΔT*m

Q is energy, S specific heat of ice = 2.06J/g°C, ΔT is change in temperature = 0°C - -10°C = 10°C and m is mass of ice = 10g

Q = 2.06J/g°C*10°C*10g

Q = 206J

Change from solid to liquid:

The heat of fusion of water is 333.55J/g. That means 1g of ice requires 333.55J to be converted in liquid. 10g requires:

Q = 333.55J/g*10g

Q = 3335.5J

Increasing temperature of liquid water from 0°C - 100°C:

Q = S*ΔT*m

Q is energy, S specific heat of ice = 4.18J/g°C, ΔT is change in temperature = 100°C - 0°C = 100°C and m is mass of water = 10g

Q = 4.18J/g°C*100°C*10g

Q = 4180J

Change from liquid to gas:

The heat of vaporization of water is 2260J/g. That means 1g of liquid water requires 2260J to be converted in gas. 10g requires:

Q = 2260J/g*10g

Q = 22600J

Increasing temperature of gas water from 100°C - 120°C:

Q = S*ΔT*m

Q is energy, S specific heat of gaseous water = 1.87J/g°C, ΔT is change in temperature = 20°C and m is mass of water = 10g

Q = 1.87J/g°C*20°C*10g

Q = 374J

Total Energy:

206J + 3335.5 J + 4180J + 22600J + 374J =

30695.5J =

30.7kJ

5 0
3 years ago
3. What is an element?​
laila [671]

Answer:

copper

Explanation:

it's on the periodic table of elements

7 0
3 years ago
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