The density of the gas is obtained as 0.55 g/L.
We can find the density of the gas using the relation;
PM = dRT
P = pressure of the gas
M = molar mass of the gas
d = density of the gas
R = gas constant
T = temperature
Now;
P = 29.9 kPa
R = 8.314 L·kPa mol·K.
T = 147°C + 273 = 420 K
d = ?
M = 64 g/mol
Substituting values;
d = PM/RT
d = 29.9 kPa × 64 g/mol/ 8.314 L·kPa mol-1K-1 420 K
d = 1913.6/3491.88
d = 0.55 g/L
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<h3><u>Answer;</u></h3>
The actual binding energy is 8.48 Mev
<h3><u>Explanation;</u></h3>
The nucleus of tritium contains one proton and two neutrons,
Therefore; For the Tritium nucleus, the binding energy may be computed as shown below:
Total mass of 1 protons = 1 × 1.00728 = 1.00728 amu
Total mass of 2 neutrons = 2 × 1.00866 = <u>2.01732 amu
</u>
Total mass of nucleons = 3.02460amu
Atomic mass of tritium = 3.01605 amu
Mass defect Dm = 0.00855 amu
But; 1 amu =931.5 MeV
Thus; Binding energy of Tritium = 0.00855 amu × 931.5 MeV/amu
= 7.964325 MeV, approximately closer to the actual 8.48 MeV.
Answer:
0.3097 moles of an nonionizing solute would need to be added.
Explanation:
Molal elevation constant =
Normal boiling point of ethanol =
Boiling of solution =
Moles of nonionizing solute = n
Mass of ethanol (solvent) = 47.84 g
Elevation boiling point:
n = 0.3097 mol
0.3097 moles of an nonionizing solute would need to be added.
Answer:
Sulfur
Explanation:
The reaction of the following question is as follows:
Na₂S₂O₃ (aq) + 2HCl(aq) --------------⇒2NaCl (aq) + H₂O(l) + SO₂(aq) + S (s)
Precipitate is sulfur.
As the acid is cooled, crystals of the hemi-hydrate began to form. the remaining solution will become dilute and will have a lower freezing point. therefore the acid will not freeze solid.