Answer: An amount of
heat is required to raise the temperature of 4.64kg of lead from 150°C to 219°C.
Explanation:
Given: mass of lead = 4.64 kg
Convert kg into grams as follows.



The standard value of specific heat of lead is
.
Formula used to calculate heat is as follows.

where,
q = heat energy
m = mass of substance
C = specific heat of substance
= change in temperature
Substitute the value into above formula as follows.

Thus, we can conclude that
heat is required to raise the temperature of 4.64kg of lead from 150°C to 219°C.
Answer:
The common name for 2-butanone, a readily available solvent, is B-butanone
Answer:

Explanation:
Hello,
In this case, we use the ideal gas equation to compute the volume as shown below:

Nonetheless we are given mass, for that reason we must compute the moles of gaseous fluorine (molar mass: 38 g/mol) as shown below:

Thus, we compute the volume with the proper ideal gas constant, R:

Best regards.
No the sun is the biggest star in the universe.