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soldi70 [24.7K]
3 years ago
9

The melting point of h2o is 0 degrees celsius. this is the same as its:

Chemistry
1 answer:
professor190 [17]3 years ago
6 0
This is the same as its freezing point

hope this helps
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How many liters of volume is one mole of gas at standard temperature and<br> pressure?
horsena [70]

22.7 liters

The molar volume of an ideal gas depends on the temperature and pressure. One mole of any ideal gas occupies 22.7 liters at 0 0C and 1 bar (STP).

Hope this helped

3 0
2 years ago
The monovalent salt concentration (the predominant solute in the blood cell) for a sample of red blood cells is 0.13 moles/liter
11111nata11111 [884]

Answer:

The osmotic pressure of cell is 648.3 KPa

Explanation:

As we know the osmotic pressure is equal to

\pi = icRT

Where

i is the Van Hoff factor

c is the concentration of solution

R is the ideal gas constant

and T is the temperature.

Substituting the given values, we get -

\pi = 2 * 0.13 * 0.08206 * 300\\

\pi = 648.3 KPa

4 0
2 years ago
Magnesium reacts steadily with hydrochloric acid
balu736 [363]

Magnesium + Hydrocloric acid -> Magnesium chloride + hydrogen

You can observe a single displacement reaction

"Describe to show that the has formed is hydrogen"

I don't know what you mean. I can show the chemical equation though.

Mg(s) + 2 HCl(aq) --> MgCl 2(aq) + H 2(g)

3 0
3 years ago
Based on the concept of the global conveyor belt, what happens to ocean water as it moves from Antarctica to the equator?
Korolek [52]

Answer:

I think the answer is C

Explanation:

5 0
2 years ago
Read 2 more answers
A buffer consists of 0.120 M HNO2 and 0.150 M NaNO2 at 25°C. pka of HNO2 is 3.40. a. What is the pH of the buffer? b. What is th
Mashcka [7]

Explanation:

It is known that K_{a} of HNO_{2} = 4.5 \times 10^{-4}.

(a)  Relation between K_{a} and pK_{a} is as follows.

                       pK_{a} = -log (K_{a})

Putting the values into the above formula as follows.

                      pK_{a} = -log (K_{a})

                                    = -log(4.5 \times 10^{-4})

                                     = 3.347

Also, relation between pH and  pK_{a} is as follows.

              pH = pK_{a} + log\frac{[conjugate base]}{[acid]}

                     = 3.347+ log \frac{0.15}{0.12}

                    = 3.44

Therefore, pH of the buffer is 3.44.

(b)   No. of moles of HCl added = Molarity \times volume

                                            = 11.6 M \times 0.001 L

                                             = 0.0116 mol

In the given reaction, NO^{-}_{2} will react with H^{+} to form HNO_{2}

Hence, before the reaction:

No. of moles of NO^{-}_{2} = 0.15 M \times 1.0 L

                                           = 0.15 mol

And, no. of moles of HNO_{2} = 0.12 M \times 1.0 L

                                               = 0.12 mol

On the other hand, after the reaction :  

No. of moles of NO^{-}_{2} = moles present initially - moles added

                                          = (0.15 - 0.0116) mol

                                          = 0.1384 mol

Moles of HNO_{2} = moles present initially + moles added

                               = (0.12 + 0.0116) mol

                                = 0.1316 mol

As, K_{a} = 4.5 \times 10^{-4}

           pK_{a} = -log (K_{a})

                         = -log(4.5 \times 10^{-4})

                         = 3.347

Since, volume is both in numerator and denominator, we can use mol instead of concentration.

As, pH = pK_{a} + log \frac{[conjugate base]}{[acid]}

            = 3.347+ log {0.1384/0.1316}

            = 3.369

            = 3.37 (approx)

Thus, we can conclude that pH after the addition of 1.00 mL of 11.6 M HCl to 1.00 L of the buffer solution is 3.37.

6 0
3 years ago
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