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sergejj [24]
3 years ago
5

* WILL GIVE BRAINLIEST TO CORRECT ANSWER *

Physics
1 answer:
stepan [7]3 years ago
3 0

I would say food but like they take weight too

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The graph is tied to the reading
AleksandrR [38]
I. Positive acceleration increases velocity. Negative acceleration decreases velocity. runner A sped up until the finish line and then slowed to a stop.

ii. Zero a acceleration implies a constant, unchanging velocity not a zero velocity. runner B achieved some velocity prior to 8s and is moving and must slow down to reach a stop.

iii. None. No aspects of this reasoning are correct. Everything she says is wrong. See iv for what/why.

iv. The sign on acceleration denotes the direction of *change in velocity* not change in direction. The sign on velocity can denote change in direction but only “forward” or “reverse” along a particular path. Cardinal direction is not indicated, generally, by the sign on velocity. It may correspond to North/South situationally but it is not an built-in feature of velocity and its sign. For example, if you are traveling with positive velocity and turn left to continue your journey you still have a positive velocity in the new direction. In fact, if you turn left again, traveling in the opposite direction as the one you started with your velocity would still be positive… in the new direction. The velocity relative to original direction could be said to be negative but that would be a confusing way to describe a journey. Maybe if you stopped the vehicle and moved in reverse, you could meaningfully say velocity was negative.
5 0
3 years ago
Suppose the line on a distance-versus-time graph and the line on a speed-versus-time graph are both slanted straight lines going
lesya [120]
No, because the distance-time would show a constant velocity but the velocity-time graph shows an increasing velocity.
4 0
4 years ago
How much would a 70 kg student weigh on Pluto? (massPluto = 1.25 x 1022 kg, radiusPluto = 1.20 x 106 m)
mote1985 [20]

Answer: the weight would be 4.6 (I think i don’t know))

Explanation:

6 0
3 years ago
A 0.017-kg acorn falls from a position in an oak tree that is 18.5 meters above the ground.
Marianna [84]

Answer:

Part a)

Final speed of the corn is 19.05 m/s

Part b)

Kinetic energy of the corn is 3.1 J

Explanation:

Part a)

As we know that the initial position of the corn is

h = 18.5 m

now we also know that it will fall from rest and moving under constant acceleration so we will have

v_f^2 - v_i^2 = 2 a d

v_f^2 - 0 = 2(9.81)(18.5)

v_f = 19.05 m/s

Part b)

Kinetic energy of the corn is given as

K = \frac{1}{2}mv^2

K = \frac{1}{2}(0.017)(19.05)^2

K = 3.1 J

4 0
4 years ago
What statement most accurately classifies this cell?
iogann1982 [59]

Answer:

D It is an animal cell.

Explanation:

6 0
4 years ago
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