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V125BC [204]
3 years ago
8

The specific heat of silver is 0.234 j/(g·c). calculate the amount of energy that is needed to raise the temperature of 175 g of

silver from 22.5°c to 40.0°c.
Chemistry
1 answer:
Elodia [21]3 years ago
3 0
Heat energy is supplied to materials and can cause an increase in temperature of the material. the formula is as follows
H = mcΔt
where H - heat energy 
m - mass of material 
c - specific heat 
Δt - change in temperature  - 40.0 °C - 22.5 °C = 17.5 °C
substituting the values 
H = 175 g x 0.234 Jg⁻¹°C⁻¹ x 17.5 °C
H = 716.6 J 
716.6 J is required 
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How much concentrated solution would it take to prepare 2.75 L of 0.400 M HCl upon dilution with water
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Solve for mL of the concd HCl solution.
7 0
2 years ago
If 5.0 liters H2 (g) at STP is heated to a temperature of 985, pressure remaining constant, the new volume of the gas will be?
vlada-n [284]

Answer:

V_2=18 \ L \ H_2

General Formulas and Concepts:

<u>Chemistry - Gas Laws</u>

  • STP (Standard Conditions for Temperature and Pressure) = 22.4 L per mole at 1 atm, 273 K
  • Charles' Law: \frac{V_1}{T_1} =\frac{V_2}{T_2}

Explanation:

<u>Step 1: Define</u>

Initial Volume: 5.0 L H₂ gas

Initial Temp: 273 K

Final Temp: 985 K

Final Volume: ?

<u>Step 2: Solve for new volume</u>

  1. Substitute:                    \frac{5 \ L \ H_2}{273 \ K} =\frac{x \ L \ H_2}{985 \ K}
  2. Cross-multiply:             (5 \ L \ H_2)(985 \ K) = (x \ L \ H_2)(273 \ K)
  3. Multiply:                        4925 \ L \ H_2 \cdot K = 273x \ L \ H_2 \cdot K
  4. Isolate <em>x</em>:                       18.0403 \ L \ H_2 = x
  5. Rewrite:                         x=18.0403 \ L \ H_2

<u>Step 3: Check</u>

<em>We are given 2 sig figs as the smallest. Follow sig fig rules and round.</em>

<em />18.0403 \ L \ H_2 \approx 18 \ L \ H_2<em />

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Why did we have you determine the reaction rate using reactant consumed per unit of time instead of product formed per unit of t
Vsevolod [243]

Answer:Rate of reaction can be determined in terms of concentration of reactants consumed or concentration of product formed per unit time

Explanation: For the reaction below

A ===>B

The reactant is A while the product given is B.

Reaction rate = Δ[B]/Δt = -Δ[A]/Δt

The concentration of A will decrease with time while the concentration of B will increases with time.

The negative sign in -Δ[A]/Δt is to convert the expression to positive since the change will always be negative (decreases)

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