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Answer:
9.606 grams of citric acid are present in 125 mL of a 0.400 M citric acid solution.
Explanation:
Molarity : It is defined as the number of moles of solute present in one liter of solution. Mathematically written as:

Moles of citric acid = n
Volume of the citric acid solution = 125 mL =125 × 0.001 L= 0.125 L
(1 mL = 0.001L)
Molarity of the citric acid solution = 0.400 M

n = 0.400 M × 0.125 L = 0.05 moles
Mass of 0.05 moles of citric acid :

9.606 grams of citric acid are present in 125 mL of a 0.400 M citric acid solution.
Answer:
It tells how quickly products will be made.
Explanation:
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Mass of CO₂ = 132 g
<h3>Further explanation
</h3>
A mole is a number of particles(atoms, molecules, ions) in a substance
This refers to the atomic total of the 12 gr C-12 which is equal to 6.02.10²³, so 1 mole = 6.02.10²³ particles
Can be formulated :
N = n x No
N = number of particles
n = mol
No = 6.02.10²³ = Avogadro's number
mole also can be formulated :

moles of CO₂ = 3
mass of CO₂(MW=44.01 g/mol) :
