When a beam of light passes at an oblique angle into a material of lower optical density, the angle of
1 answer:
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Answer:
16.5 kwh and 59400 kJ.
Explanation:
kWh is a measure of energy that is equivalent to the power in kw times the number of hours the device worked.
In this case, it would be equal to:
1 kw also means 1kj of energy spent per second. With this, we calculate the amount of energy in kJ spent by the resistance:
Answer:
a = 3.27 m/s²
v = 2.56 m/s
Explanation:
given,
mass A = 1 kg
mass B = 2 kg
vertical distance between them = 1 m
a = 3.27 m/s²
The speed of the system at that moment is:
v² = u² + 2×a×s
v² = 0² + 2× 3.27 × 1
v ² = 6.54
v = 2.56 m/s