Answer:
The number of atoms is the same in the reactants and in the products, and the total mass is the same in the reactants and in
the products
Explanation:
For an equation to termed balance, the number of atoms of elements in the reactants must be equal to the number of atoms of the same element in the product.
The law of conservation of mass states that matter can neither be created nor destroyed during a chemical reaction but changes from one form to another. An unbalanced equation simply means that matter have been created or destroyed. This implies that balancing equation supports the laws of conservation of mass
The central Sn atom is bonded to the three Cl atoms and has one nonbonding pair on it. Therefore, the Sn atom has four electron domains around it. The resulting electron-domain geometry is tetrahedral (Table 9.1) with three of the corners occupied by the bonding pairs of electrons.
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Water has greatest boiling and melting points because strong hydrogen bonds between water molecules (intermolecular force). That is because oxygen has largest electronegativity and smallest atomic radius of all elements in group. Other elements in this group do not form hydrogen bonds and they are gasses in room temperature, water is liquid and their boiling and melting points are lower. Boiling and melting point of hydrides gradually increases from H₂S to H₂Te because of increase of the radius and molecular mass of atoms from sulfur to tellurium, that is why intermolecular force of attraction of molecules increases. <span>
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Types of Bonds can be predicted by calculating the difference in electronegativity.
If, Electronegativity difference is,
Less than 0.4 then it is Non Polar Covalent
Between 0.4 and 1.7 then it is Polar Covalent
Greater than 1.7 then it is Ionic
For Li and O,
E.N of Oxygen = 3.44
E.N of Lithium = 0.98
________
E.N Difference 2.46 (Ionic Bond)
For Cl and F,
E.N of Fluorine = 3.98
E.N of Chlorine = 3.16
________
E.N Difference 0.82 (Mildly Polar Covalent Bond)
For Ca and S,
E.N of Sulfur = 2.58
E.N of Calcium = 1.00
________
E.N Difference 1.58 (Polar Covalent Bond)
Answer:
2Al + 6HBr → 2AlBr₃ + 3H₂
Explanation:
2Al + 6HBr → 2AlBr₃ + 3H₂
2 Al in reactant side
2 Al in product side
6 Br in reactant side
6 (2x3) Br in reactant side
6 H in reactant side
6 H in product side (3x2)