Answer:
The answer to your question is:
a) 0.023 mol of CdS
b) 0.12 mol of MoO3
c) 7.3 mol of AlPO4
Explanation:
a) CdS
MW = 112.4 + 32
= 144 g
144g ------------------ 1 mol
3.28g -------------- x
x = (3.28 x 1) / 144
x = 0.023 mol
b) MoO3
MW = 96 + 3(16) = 144 g
144g ------------------- 1 mol
17.5g ----------------- x
x = (17.5 x 1) / 144
x = 0.12 mol
c) AlPO4
MW = 27 + 31 + 4(16)
MW = 122 g
122 g ------------------ 1mol
890 g ------------------ x
x = (890 x 1) / 122
x = 7.3 mol of AlPO4
Answer:
Significant figures are a measure of <u><em>precision</em></u>.
Explanation:
The significant figures of a number are those that have a real meaning and, therefore, provide some information. Therefore, the set of digits that are known with certainty in a measure are called significant figures and are the digits of a number considered non-null.
Any experimental measurement is inaccurate and must be expressed with its significant figures.
In this way, significant figures express the precision of a measuring tool.
Explanation:
Given parameters:
Mass of Br-79 = 78.918 amu
Abundance = 50.69%
Unknown:
Mass of Br - 81 = ?
Solution:
Relative Atomic mass of Br = 80
The proportion by which each fraction of an isotope occurs in nature is called the geonormal abundance.
RAM = Ma Ba + McBc
The formula above is used to find the average mass of the given isotopes.
Since we know the percentage abundance of Br-79, that of Br-81 = 100-50.69= 49.31%
RAM = Ma Ba + McBc
RAM = relative atomic mass
Ma Ba = mass and abundance of Br-79
McBc = mass and abundance of Br-81
80 = (78.918 x
) + (
x C)
80 = 40 + 0.49C
0.49C = 40
C =
= 81.63amu
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