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2 years ago

Why does an ionic compound conduct an electric current when the compound is melted but not when it is in the solid state?

Chemistry

1 answer:

skelet666 [1.2K]2 years ago

6 0

When in solid state the charged particles (ions) are NOT free to move but when in melted the ions are free to move.

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Balance the following equation: K+ H2O + H2 + KOH

alex41 [277]

Answer:

2K + 2H2O → H2 + 2KOH

Explanation:

Find how many atoms you have on both sides then add 2 to both sides.

Reactant: Products:

K: 1+1=2 K: 1+1=2

H: 2+2=4 H: 3+1=4

O: 1+1=2 O: 1+1=2

Therefore it is balanced. Hope this helps

6 0

2 years ago

A solution made by dissolving 33 mg of insulin in 6.5 mL of water has an osmotic pressure of 15.5 mmHg at 25°C. Calculate the mo

Liula [17]

Answer: The molar mass of the insulin is 6087.2 g/mol

Explanation:

To calculate the concentration of solute, we use the equation for osmotic pressure, which is:

$\pi=iMRT$

Or,

$\pi=i\times \frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}\times RT$

where,

$\pi$ = osmotic pressure of the solution = 15.5 mmHg

i = Van't hoff factor = 1 (for non-electrolytes)

Mass of solute (insulin) = 33 mg = 0.033 g (Conversion factor: 1 g = 1000 mg)

Volume of solution = 6.5 mL

R = Gas constant = $62.364\text{ L.mmHg }mol^{-1}K^{-1}$

T = temperature of the solution = $25^oC=[273+25]=298K$

Putting values in above equation, we get:

$15.5mmHg=1\times \frac{0.033\times 1000}{\text{Molar mass of insulin}\times 6.5}\times 62.364\text{ L.mmHg }mol^{-1}K^{-1}\times 298K\\\\\text{molar mass of insulin}=\frac{1\times 0.033\times 1000\times 62.364\times 298}{15.5\times 6.5}=6087.2g/mol$

Hence, the molar mass of the insulin is 6087.2 g/mol

8 0

2 years ago

What is the hyphen notation of nitrogen

vovikov84 [41]

N-16

7 protons & 9 neutrons
7 + 9 = 16

6 0

3 years ago

How much would a 50-kg object weigh on Mercury (gravity on Mercury is 3.59 m/s2)?

Andreyy89

Gravitational Acceleration or W=Mg so... Q1: W(earth)=50, W(X)=500 ---> g(X)=10*g(earth)=10*9.8=98 --> C is correct. Q2: M=W/g --> M=735/9.8=75 ---> B is correct. Q3: W=Mg=50*3.59=179.5 N ---> B is correct

4 0

2 years ago

What can you calculate with the Henderson-Hasselbalch equation

Mamont248 [21]

Answer:

Actually, The Henderson - Hasselbalch equation allows you to calculate the pH of the buffer by using the pKa of the weak acid and the ratio that exists between the concentrations of the weak cid and conjugate base. The pKa of formic acid is equal to 3.75. In this case, the pH of the solution will be equal to the acid's pKa .

5 0

3 years ago