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Dmitriy789 [7]
3 years ago
12

How many moles of NaOH are present in 65.00 g of NaOH(s)? *

Chemistry
1 answer:
schepotkina [342]3 years ago
6 0

Answer:

<h2>The answer is option B</h2>

Explanation:

To find the number of moles we must first find the molar mass of the compound after that we use the formula

n =  \frac{m}{M}

where

n is the number of moles

M is the molar mass

m is the mass

M(Na) = 23 , M(O) = 16 , M(H) = 1

Molar mass ( NaOH ) = 23+ 16 + 1

= 40 g/mol

mass = 65 g

Substitute the values into the above formula and solve

That's

n =  \frac{65}{40}  =  \frac{13}{8}

We have the final answer as

<h3>1.625 moles </h3>

Hope this helps you

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Answer:

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