17) f(x) = 16/(13-x).
In order to find domain, we need to set denominator expression equal to 0 and solve for x.
And that would be excluded value of domain.
13-x =0
Adding x on both sides, we get
13-x +x = x.
13=x.
Therefore, domain is All real numbers except 13.
18).f(x) = (x-4)(x+9)/(x^2-1).
In order to find the vertical asymptote, set denominator equal to 0 and solve for x.
x^2 -1 = 0
x^2 -1^2 = 0.
Factoring out
(x-1)(x+1) =0.
x-1=0 and x+1 =0.
x=1 and x=-1.
Therefore, Vertical asymptote would be
x=1 and x=-1
19) f(x) = (7x^2-3x-9)/(2x^2-4x+5)
We have degrees of numberator and denominator are same.
Therefore, Horizontal asymptote is the fraction of leading coefficents.
That is 7/2.
20) f(x)=(x^2+3x-2)/(x-2).
The degree of numerator is 2 and degree of denominator is 1.
2>1.
Degree of numerator > degree of denominator .
Therefore, there would no any Horizontal asymptote.
Answer:
Center = (5,-3) and radius = 7
Step-by-step explanation:
(5) If Oskar bisects the diameter of a circle, what is he trying to construct the radius of the circle.
(6) The given equation is :
The general equation of circle is given by :
...(1)
Where
(a,b) are the coordinates of the centre and r is the radius.
The given equation can be written as :
..(2)
Comparing equation (1) and (2) we get :
a = 5, b = -3 and r = 7
So,
Center = (5,-3) and radius = 7
Hence, this is the required solution.
Answer:
-5.65685424949
Step-by-step explanation:
Answer:
23.78
Step-by-step explanation:
CAH
x/25
cos18=x/25
25cos18=x
x=23.78
Answer: Undefined
The x coordinates are the same, so a vertical line forms. All vertical lines have undefined slopes.
We can see it through the slope formula
m = (y2-y1)/(x2-x1)
m = (3-(-6))/(2-2)
m = (3+6)/(2-2)
m = 9/0
We cannot divide by zero, so the result is undefined.
