In a double covalent bonds there are 4 valence electrons that are shared.
D. The final substance in Beaker A is a mixture and in Beaker B is a pure substance.
To find for the oxidizing agent, first let us write the
half reactions of this complete chemical reaction:
Ca = Ca2+ + 2e- <span>
2 H+ + 2e- = H2</span>
The oxidizing agent
would be the substance of the element that is reduced. We know that an element
is reduced when an electron is added to it. In this case, the element being
reduced is H. Therefore the oxidizing agent is HNO3.
Answer:
<span>HNO3</span>
