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miskamm [114]
4 years ago
15

Iodine-123, which is used for diagnostic imaging in the thyroid, has a half-life of 13 hours. If 50.0 mg of I-123 were prepared

at 8:00 A.M. on Monday, how many mg remain at 10:00 A.M. on the following day
Chemistry
1 answer:
cupoosta [38]4 years ago
6 0

Answer: 12.5 mg

Explanation:

The half-life of Iodine -123 is 13 hours.

Between 8 am on Monday and 10 am on Tuesday will be 26 hours.

After the first 13 hours, the Iodine should be left with half of its initial quantity

= 50/2

= 25 mg

There are now 13 hours remaining meaning that the Iodine will be half of the 25mg after that period.

= 25/2

= 12.5 mg.

12.5 mg remain at 10 am the next day.

Please do react or comment if you need any clarification or if the answer helped you. This would help other users as well. Thank you.

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Zinc phosphate is used as a dental cement. A 50.00-mg sample is broken down into its constituent elements and gives 16.58 mg oxy
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Answer:

Zn3P2O8

Explanation:

In this particular question, it is necessary to convert the respective masses to percentages. We convert to percentages by placing each mass over the total mass and multiplying by 100%. Since the total is 50mg, conversion to percentage can be done by multiplying the masses by 2 as 100/50 is 2

For Oxygen = 16.58 * 2 = 33.16%

For phosphorus = 8.02 * 2 = 16.04%

For zinc = 25.40 * 2 = 50.80%

We then proceed to divide these percentages by their respective atomic masses. The atomic mass of oxygen, phosphorus and zinc are 16, 31 and 65 respectively.

O = 33.16/16 = 2.0725

P = 16.04/31 = 0.5174

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Now, we divide by the smallest value which is that of the phosphorus

O = 2.0725/0.5174 = 4

P = 0.5174/0.5174 = 1

Zn= 0.7815/0.5174 = 1.5

Now, we need to multiply through by 2. This yields: O = 8, P = 2 and Zn = 3

The empirical formula is thus: Zn3P2O8

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You have a cup of hot water and you dissolve as much salt in it as possible. You then put the cup into the refrigerator and you
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