3 years ago

The amount of potential energy depends on the objects _________ and position

Physics

2 answers:

kirill115 [55]3 years ago

5 0

Mass Urdu fight him in

disa [49]3 years ago

4 0

Mass would be the answer

You might be interested in

Which two elements have the same number of valence electrons?

UNO [17]

Answer:

The answer is A. C and O..

4 0

3 years ago

Read 2 more answers

2. If you want 0. 250 a (250 milliamps) to flow around a circuit with a resistance of 400 ohms, what voltage do you need?

grigory [225]

Answer:

0.000625 V

Explanation:

The formula linking current , resistance and voltage is :

V = I/R

Voltage = Current / Resistance

Now we substitute values given in question :

Voltage = 0.250 / 400

Voltage (V) = 0.000625

Our final answer is 0.000625 V

Hope this helped and have a good day

5 0

1 year ago

CN you help me with this question?

qaws [65]

25% i believe because if were talking 50 percent half it would be 25.

8 0

2 years ago

What is the repulsive force between two pith balls that are 8.00 cm apart and have equal charges of −25.0 nc? g?

Daniel [21]

To calculate the force between two negative charges, we use the formula which is given by the Coulomb`s Law as

$F=\frac{kq_{1}q_{2} }{r^{2} }$

Here, $q_{1}$ and $q_{2}$ are the charges on the pith balls, r is the separation between the charges and k is constant and its value is $8.99\times 10^9 N m^2/C^2$ .

Given $q_{1} =q_{2} =-25 nC=-25\times 10^{-9}C$ and $r=8 cm=8\times10^{-2} m$ .

Substituting these values in above formula we get,

$F= 8.99\times 10^9 N m^2/C^2\frac{(-25\times 10^{-9}C)(-25\times 10^{-9}C)}{(8\times10^{-2} m)^2} \\\\\ F= 877929.7\times 10^{-9} N\\\\F=8.8\times10^{-4}N$

Thus, the repulsive force between two pith balls is $8.8\times10^{-4}N$ .

7 0

3 years ago

Read 3 more answers

Sports car goes from a velocity of zero to a velocity of 12 m/s East in two seconds. What is the cars acceleration?

bogdanovich [222]

Answer:

6 m/sec

Explanation:

12/2=6

7 0

3 years ago