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ser-zykov [4K]
2 years ago
11

Does the buoyant force on a submerged object depend on the volume of the object or on the weight of the object?.

Physics
1 answer:
stich3 [128]2 years ago
4 0

Answer:

The buoyant force on a submerged object depends upon the volume of the object.

Explanation:

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The orbits of most comets
Ludmilka [50]

Answer:

option B

Explanation:

The correct answer is option B

Comets are the frozen snowball that is made of different gases and which rotates around the sun.

Comets are generally icy but when comets come near to the sum they get warm and release gasses which can be seen from the earth.

Comet produces a visible atmosphere or coma.

examples of comets are  Halley's Comet, Comet Encke.

The orbit of comets is entirely beyond the orbit of Neptune.

4 0
3 years ago
Pls answer these ASAP....THANK YOU...
natali 33 [55]

Density = (mass) / (volume) <== MEMORIZE THIS !

1).  Mass = 50 g.  Volume = 100 cm³.  Density = (mass) / (volume)

===================================

2).  Volume = (length) ·(width) ·(height) = (4cm) ·(4cm) ·(4cm) = 64 cm³

Mass = 672 g.  Density = (mass) / (volume)

===================================

3).  Volume = (length) ·(width) ·(height)

Length = 1 meter = 100 cm

Width = 10 cm = 10 cm

Height = 22 mm = 2.2 cm

Volume = (100 cm) (10 cm) (2.2 cm) = 2,200 cm³

Mass = 42,460 g

Density = (mass) / (volume)

3 0
2 years ago
The period of a wave is the reciprocal of its ______________.
Hunter-Best [27]
Frequency

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6 0
3 years ago
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Andrews [41]

Answer:

what

Explanation:

6 0
3 years ago
Two stationary positive point charges, charge 1 of magnitude 3.25 nC and charge 2 of magnitude 2.00 nC , are separated by a dist
Liula [17]

Complete Question

Two stationary positive point charges, charge 1 of magnitude 3.25 nC and charge 2 of magnitude 2.00 nC , are separated by a distance of 58.0 cm . An electron is released from rest at the point midway between the two charges, and it moves along the line connecting the two charges.

Required:

What is the speed of the electron when it is 10.0 cm from the +3.25-nC charge?

Answer:

The velocity is v = 80.82 \ m/s

Explanation:

From  the question we are told that

   The magnitude of charge one is  q_1 =  3.25 nC  =  3.25 *10^{-9} \  C

   The  magnitude of charge two  q_2  =  2.00 \ nC  =  2.00 *10^{-9} \ C

   The distance of separation is   d =  58.0 \ cm  =  0.58 \ m

 

Generally the electric potential of the electron at the midway point is mathematically represented as

         V  =  \frac{ q_1 }{\frac{d}{2} }  + \frac{ q_2}{\frac{d}{2} }

substituting values

         V  =  \frac{ 3.25 *10^{-9} }{\frac{ 0.58}{2} }  +  \frac{ 2 *10^{-9} }{\frac{ 0.58}{2} }

          V  =  1.8103 *10^{-8} \  V

Now when the electron is 10 cm   =  0.10 m  from charge 1 , it is  (0.58 - 0.10 =  0.48 m ) m from charge two

Now the electric potential  at that point is mathematically represented as

       V_1  =  \frac{q_1}{ 0.10}  +  \frac{q_2}{ 0.48}

 substituting values

      V_1  =  \frac{3.25 *10^{-9}}{ 0.10}  +  \frac{2.0*10^{-9}}{ 0.48}

      V_1  = 3.67*10^{-8}  \ V

Now the law of energy conservation ,

   The  kinetic energy of the electron  =  potential energy of the electron

i.e     \frac{1}{2} * m * v^2  =  [V_1 -  V]* q

where q is the magnitude of the charge on the electron with value

      q = 1.60  *10^{-19} \ C

While m is the mass of the electron with value  m = 9.11*10^{-31} \  kg

        \frac{1}{2} * 9.11 *10^{-19} * v^2  =  [ (3.67 -  1.8103) *10^{-8}]* 1.60 *10^{-19}

         v = \sqrt{6532.4}

        v = 80.82 \ m/s

 

4 0
3 years ago
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