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Alina [70]
3 years ago
12

What is the product of glycolysis?

Chemistry
1 answer:
sp2606 [1]3 years ago
5 0
I believe the correct answer would be D. 
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In which chemical reaction will the heat content of the reactants be more than that of the products?
kotegsom [21]
D.

The greater heat content will be observed as heat energy released from the reaction mixture.
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Volume is a measurement of how fast particles of a substance are moving.
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Which focuses on the composition of matter
riadik2000 [5.3K]
There is no info for anyone to answer this
3 0
3 years ago
Provide the reagents necessary to carry out the following conversion. Group of answer choices KMnO4, NaOH,H2O KMnO4, H3O , 75oC
bonufazy [111]

Answer:

KMnO4,H3O^+,75°C

Explanation:

The conversion of cyclohexene to trans-1,2-cylohexanediol is an oxidation reaction. Alkenes are oxidized in the presence of potassium permanganate and acids to yield the corresponding diols.

These diols may also be called glycols. They are molecules that contain two -OH(hydroxyl) groups per molecule. The reaction closely resembles the addition of the two -OH groups of hydrogen peroxide to an alkene.

The bright color of potassium permanganate disappears in this reaction so it can be used as a test for alkenes.

3 0
3 years ago
The equation for photon energy, E, is E=hc/λ
Leni [432]

Answer:

The wavelength, λ, of a photon that has an energy of E = 3.92×10⁻¹⁹ J is 5.054*10⁻⁷ m

Explanation:

The wavelength is defined for every periodic wave, that is, for the type of wave that repeats itself with exactly the same shape every given interval of time. It is the distance between two points from which the wave repeats.

Radiation is the emission, propagation and transfer of energy in any medium in the form of electromagnetic waves or particles.

The energy carried by electromagnetic radiation travels by waves. This energy is transmitted grouped in small "quanta" of energy called photons. The energy of a photon is measured in Joules (J) and is

E=\frac{h*c}{wavelength}

Being:

  • E=3.92×10⁻¹⁹ J
  • h= 6.626×10⁻³⁴ J⋅s (Planck's constant)
  • c = 2.99×10⁸ m/s (the speed of light)
  • wavelength=?

and replacing:

3.92*10^{-19}J =\frac{6.626*10^{-34}J.s*2.99*10^{8}\frac{m}{s}   }{wavelength}

you get:

wavelength =\frac{6.626*10^{-34}J.s*2.99*10^{8}\frac{m}{s}   }{3.92*10^{-19}J}

wavelength= 5.054*10⁻⁷ m

<u><em>The wavelength, λ, of a photon that has an energy of E = 3.92×10⁻¹⁹ J is 5.054*10⁻⁷ m</em></u>

6 0
3 years ago
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