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svetoff [14.1K]
3 years ago
14

What is the approximate wavelength of a light whose second-order dark band forms a diffraction angle of 15.0° when it passes thr

ough a diffraction grating that has 250.0 lines per mm?
Physics
1 answer:
Natalija [7]3 years ago
7 0
The answer to this would be 414 nm
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A car traveling 26 m/s starts to decelerate steadily. It comes to a complete stop in 13 seconds. What is it's acceleration. ___m
V125BC [204]
To find acceleration you subtract the final velocity and subtract it from the initial velocity and you divide the difference by the total time.

so you take the final velocity which is 0 m/s because the car comes to a complete stop.

then you subtract that from the initial which is 26 m/s

in other words:

0m/s - 26 m/s = -26 m/s

then you divide it by the total time which is 13 s

-26 m/s / 13 s

so you get

-2 m/s^2
6 0
3 years ago
1. A point scored when the ball passes between the goal posts is considered a
Maru [420]

Answer:

Goal or Field Goal

Explanation:

It is a goal in a sport like hockey or it is a field goal in football.

4 0
3 years ago
In August 2011, the Juno spacecraft was launched from Earth with the mission of orbiting Jupiter in 2016. The closest distance b
Vikentia [17]

(a) 8927 mi/h

In order to calculate the average speed, we need to convert the time (t=5.0 y) into hours first. In 1 year, we have 365 days, each day consisting of 24 hours, so the time taken is:

t=(5.0 y)(365 d/y)(24 h/d)=43,800 h

The distance covered by the spacecraft is

d=391 mil. mi = 391\cdot 10^6 mi

Therefore, the average speed is just the ratio between the distance covered and the time taken:

v=\frac{d}{t}=\frac{391\cdot 10^6 mi}{43,800 h}=8,927 mi/h

(b) 35 minutes (2097 seconds)

The transmitted signals (which is a radio wave, which is an electromagnetic wave) travels back to the Earth at the speed of light:

c=3.0\cdot 10^8 m/s

Since 1 miles = 1609 metres, the distance covered  by the signal is

d=391\cdot 10^6 mi \cdot (1609 m/mi)=6.29\cdot 10^{11} m

So, the time taken by the signal will be

t=\frac{d}{v}=\frac{6.29\cdot 10^{11} m}{3.0\cdot 10^8 m/s}=2097 s

And since 1 minute = 60 sec, the time taken is

t=2097 s \cdot \frac{1}{60 s/min}\sim 35 min

7 0
3 years ago
PLEASE ANSWER NEED HELP!!!!!!!! PLEASE THE CORRECT ANSWER!!!!!!
Leya [2.2K]

Answer:

c

Explanation:

5 0
3 years ago
Please need help on this
Andrei [34K]

Q1 option 3

I hope it helps

3 0
3 years ago
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