I'm pretty sure its the first one
Explanation:
Answer:
Crisscross method is simply writing the charges crossly near each element. Since oxidation number of Mg (metal) is +2 and oxygen (nonmetal) is -2, if we cross them and write next to each; we get Mg2O2 .
Explanation:
Given parameters:
Wavelength of photon = 1.95 x 10⁻¹¹m
Unknown:
Frequency of the wave = ?
Energy of the photon = ?
Solution:
The frequency and wavelength of a wave are related by the expression;
C = Fλ
C = speed of light = 3 x 10⁸m/s
F = frequency
λ = wavelength
Insert the parameters and solve;
3 x 10⁸ = F x 1.95 x 10⁻¹¹
F = 
= 1.54 x 10¹⁹Hz
Energy of the photon is related to frequency using the expression below;
E = hF
h is the Planck's constant = 6.634 x 10⁻³⁴m²kg/s
Insert the parameters and solve;
E = 6.634 x 10⁻³⁴ x 1.54 x 10¹⁹ = 1.02 x 10⁻¹⁴J
Answer:
See below
Explanation:
Hello there!
Electronegativity is the atom's tendency to attract electrons in a chemical bond
There are two trends to electronegativity:
- Electronegativity increases from bottom to top in a group (Li has a greater electronegativity than Fr, for example)
- Electronegativity increases from left to right across a period (the further right the group, the greater the electronegativity)
Looking at a period table, Sb, Sn, Te, and I are all in the same period, so we'll need to decide which element has the highest electronegativity based on the group.
- Sn belongs to group 4A (group 14)
- Sb belongs to group 5A (group 15)
- Te belongs to group 6A (group 16)
- I belongs to group 7A (group 17)
As I belongs to group 7A, the group that is the farthest right based off of the options given, I has the highest electronegativity
Hope this helps!
