Answer: Application.
Explanation:
The question on wether to contine the use of cadavers in the lab for test is being centered around its application. Cadaver which is same as a corpse or dead body is used in crash site during automobil test in lab, some of this cadavers are been disrespected with their applications in the automobile industries because many didn’t consent to be used in those experiments or test.
Answer:
What is true about a point and shoot camera?
- They are often smaller than SLR cameras
Answer: 1.137*10^7 Btu/h.
Explanation:
Given data:
Efficiency of the plant = 4.5percent
Net power output of the plant = 150kw
Solution:
The required collection rate
QH = W/n
= 150/0.045 * 0.94782/ 1 /60 */60 Btu/h.
= 3333.333 *3412.152Btu/h.
= 11373840 Btu/h
= 1.137*10^7 Btu/h.
Answer:crane and engine I guess
Explanation:
Answer:
T₂ =93.77 °C
Explanation:
Initial temperature ,T₁ =27°C= 273 +27 = 300 K
We know that
Absolute pressure = Gauge pressure + Atmospheric pressure
Initial pressure ,P₁ = 300+1=301 kPa
Final pressure ,P₂= 367+1 = 368 kPa
Lets take temperature=T₂
We know that ,If the volume of the gas is constant ,then we can say that
![\dfrac{P_2}{P_1}=\dfrac{T_2}{T_1}](https://tex.z-dn.net/?f=%5Cdfrac%7BP_2%7D%7BP_1%7D%3D%5Cdfrac%7BT_2%7D%7BT_1%7D)
![{T_2}=T_1\times \dfrac{P_2}{P_1}](https://tex.z-dn.net/?f=%7BT_2%7D%3DT_1%5Ctimes%20%5Cdfrac%7BP_2%7D%7BP_1%7D)
Now by putting the values in the above equation we get
![{T_2}=300\times \dfrac{368}{301}\ K](https://tex.z-dn.net/?f=%7BT_2%7D%3D300%5Ctimes%20%5Cdfrac%7B368%7D%7B301%7D%5C%20K)
The temperature in °C
T₂ = 366.77 - 273 °C
T₂ =93.77 °C