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Daniel [21]
3 years ago
8

A 1,200-watt water heater is plugged into a 120-volt outlet and used for 1.5 hours. How much current runs through the water heat

er?
Physics
2 answers:
Ray Of Light [21]3 years ago
7 0

Answer:

Current (i) = 10 Ampere

Explanation:

As we know that power consumed by the electrical heater is given by the rate of electrical energy consumed by it.

So as we know that electrostatic potential energy of charge is given by

U = qV

now for electrical power we know that

P = \frac{dU}{dt}

P = \frac{d}{dt}(qV)

P = V\frac{dq}{dt}

P = Vi

so now by plug in data in this above equation we have

1200 = 120 \times i

i = 10 A

so current through the water heater will be i = 10 A

stiv31 [10]3 years ago
4 0
Current = power/voltage = 1200w/120v = 10 amperes. Constantly. Whenever the heater is turned on and heating.
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Suppose that you lift four boxes individually, each at a constant velocity. The boxes have weights of 3.0 N, 4.0 N, 6.0 N, and 2
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Answer:

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The S.I unit of work is Joules (J).

Mathematically it can be represented as,

W = F×d.................. Equation 1

d = W/F.............................. Equation 2

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(i) for the 3.0 N weight,

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d = 12/3

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d = 12/4

d = 3 m.

(iii) for the 6.0 N weight,

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d = 2 m.

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d = 12/2

d = 6 m

Therefore vertical distance of weight 3.0 N = 4 m, vertical distance of weight 4.0 N = 3 m, vertical distance of weight 6.0 N = 2 m, vertical distance of weight 2.0 N = 6 m

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3 years ago
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A 5.00-g bullet is fired into a 900-g block of wood suspended as a ballistic pendulum. The combined mass swings up to a height o
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Answer:

The value is  KE_b =0.710 \ J

Explanation:

From the question we are told that

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  The mass  of the wood is  m_w =  900 \  g  =  0.90\  kg

   The height attained by the combined mass is  h =  8.0 \ cm  =  0.08 \ m

Generally according to the law of energy conservation    

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Here KE_b is the kinetic energy of the bullet before collision.

and PE_c is the  potential  energy of the combined mass of bullet and wood at the height h which is mathematically represented as

      PE_m  =  [m_b  + m_w] *  g *  h

So

   KE_b =PE_c   = [0.005  + 0.90] * 9.8 *0.08

=> KE_b =0.710 \ J

3 0
3 years ago
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