Question

If a gas's temperature doubles and its volume remains constant, then what happens to its pressure?

Answer 1

Answer : The pressure become doubles.

Explanation :

Gay-Lussac's Law : It is defined as the pressure of the gas is directly proportional to the temperature of the gas at constant volume and number of moles.

$P\propto T$

or,

$\frac{P_1}{T_1}=\frac{P_2}{T_2}$

where,

$P_1$ = initial pressure

$P_2$ = final pressure

$T_1$ = initial temperature

$T_2$ = final temperature = $2T_1$

Now put all the given values in the above equation, we get:

$\frac{P_1}{T_1}=\frac{P_2}{2T_1}$

$\frac{P_2}{P_1}=2$

From this we conclude that, as the temperature of gas doubles then the pressure of gas become doubles because pressure is directly proportional to the temperature of gas.

Hence, the pressure become doubles.