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Ahat [919]
4 years ago
6

If a gas's temperature doubles and its volume remains constant, then what happens to its pressure?

Chemistry
1 answer:
Semenov [28]4 years ago
6 0

Answer : The pressure become doubles.

Explanation :

Gay-Lussac's Law : It is defined as the pressure of the gas is directly proportional to the temperature of the gas at constant volume and number of moles.

P\propto T

or,

\frac{P_1}{T_1}=\frac{P_2}{T_2}

where,

P_1 = initial pressure

P_2 = final pressure

T_1 = initial temperature

T_2 = final temperature = 2T_1

Now put all the given values in the above equation, we get:

\frac{P_1}{T_1}=\frac{P_2}{2T_1}

\frac{P_2}{P_1}=2

From this we conclude that, as the temperature of gas doubles then the pressure of gas become doubles because pressure is directly proportional to the temperature of gas.

Hence, the pressure become doubles.

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