1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
goldenfox [79]
4 years ago
14

Which is an example of a covalent bond? Chlorine accepts an electron from calcium to form a stable bond. Ions in a bar of pure i

ron are surrounded by a large number of valence electrons. There are less than 16 valence electrons in 2 chlorine atoms, but they form a stable bond.
Chemistry
2 answers:
sukhopar [10]4 years ago
8 0

Answer:

There are less than 16 valence electrons in 2 chlorine atoms, but they form a stable bond

Explanation:

A covalent bond occurs between nonmetal elements, or between a nonmetal and hydrogen or between hydrogen atoms. In this kind of bond, the atoms share electrons.

In the first case, chlorine is accepting electrons from calcium, which is donating. Chlorine is a nonmetal, but calcium is a metal. They form an ionic bond.

In a metal bar, like iron, there are metallic bonds: the metal loses electrons, and the cation (the metal ion) is surrounded by these electrons.

So, in a bond between two chlorine atoms, both nonmetal, there is a sharing of electrons. Both have 7 electrons in the valence shell, and each one shares one electron. They both will have 8 electrons, but the total will be 14 electrons, less than 16.

Ivenika [448]4 years ago
4 0
Chlorine + Calcium --> Ionic Bond
Iron cannot covalently bond as it is a metal
You might be interested in
What type of reaction is FeS + 2 HCl > FeCl2 + H2S?
schepotkina [342]
Double replacement means a reaction that includes two molecules that each have two different ions. After the reaction, the ions pairs have switched, which is what is shown in the above equation. A single replacement would be a very simple reactions such as: 2Fe(II)S + Ov2^2- -> 2Fe(II)O + 2S^2- A decomposition reaction would be shown as this: 2NaCl -(dissolve in water)> 2Na^+ + Clv2^- A synthesis reaction could be the exact opposite: 2Na^1+ + Clv2^1- -> 2NaCl
8 0
3 years ago
Calculate the mass of Octane needed to release 6.20 mol Co2
n200080 [17]
The combustion reaction of octane is as follow,

                           C₈H₁₈  +  25/2 O₂     →     8 CO₂  +  9 H₂O

According to balance equation,

8 moles of CO₂ are released when  =  114.23 g (1 mole) Octane is reacted

So,

      6.20 moles of CO₂ will release when  =  X g of Octane is reacted

Solving for X,
                                     X  =  (114.23 g × 6.20 mol) ÷ 8 mol

                                     X  =  88.52 g of Octane
Result:
           88.52 g of Octane is needed to release 6.20 mol CO₂.
8 0
3 years ago
What does a Stationary object line look like?
Paladinen [302]

Answer:

Explanation:It looks like a graph. Google it!

5 0
3 years ago
What is the volume, in milliliters, of 6.68 g of acetone?
Pepsi [2]
<span>Acetone has a density of 784 kg/mÂł (this you can look up). This equals 784.000 g/mÂł (kilo means 1000). Which can be converted to 0.784 g/cm3 (1 m3 is 1.000.000 cm3). A cm3 is exactly 1 ml. So 0.784 g/cm3 = 0.784 g/ml. We have 6.68 gram of acetone. 6.68 g / 0.784 g/ml = 8.52 ml. So the volume of 6.68 grams of acetone is 8.52 ml.</span>
3 0
3 years ago
Nitroglycerin is a dangerous powerful explosive that violently decomposes when it is shaken or dropped. The Swedish chemist Alfr
Ganezh [65]

Answer:

a. 4 C_3H_5N_3O_9 (l)\rightarrow 6N_2 (g) + O_2 (g) + 10 H_2O (g) + 12 CO_2 (g)

b. 146.0 g

Explanation:

Question 1 (a). Just as the problem states, liquid nitroglycerin decomposes into nitrogen gas N_2, oxygen gas O_2, water vapor H_2O and carbon dioxide CO_2. Let's write the decomposition of nitroglycerin into these 4 components:

C_3H_5N_3O_9 (l)\rightarrow N_2 (g) + O_2 (g) + H_2O (g) + CO_2 (g)

Now we need to balance the equation. Firstly, notice we have 3 carbon atoms on the left and 1 on the right, so let's multiply carbon dioxide by 3:

C_3H_5N_3O_9 (l)\rightarrow N_2 (g) + O_2 (g) + H_2O (g) + 3 CO_2 (g)

Now, we have 3 nitrogen atoms on the left and 2 on the right, so let's multiply nitrogen on the right by \frac{3}{2}:

C_3H_5N_3O_9 (l)\rightarrow \frac{3}{2}N_2 (g) + O_2 (g) + H_2O (g) + 3 CO_2 (g)

We have 5 hydrogen atoms on the left, 2 on the right, so let's multiply the right-hand side by \frac{5}{2}:

C_3H_5N_3O_9 (l)\rightarrow \frac{3}{2}N_2 (g) + O_2 (g) + \frac{5}{2} H_2O (g) + 3 CO_2 (g)

Finally, count the oxygen atoms. We have a total of 9 on the left. On the right we have (excluding oxygen molecule):

\frac{5}{2} + 6 = 8.5

This leaves 9 - 8.5 = 0.5 = \frac{1}{2} of oxygen. Since oxygen is diatomic, we need to take one fourth of it to get one half in total:

C_3H_5N_3O_9 (l)\rightarrow \frac{3}{2}N_2 (g) + \frac{1}{4} O_2 (g) + \frac{5}{2} H_2O (g) + 3 CO_2 (g)

To make it look neater without fractional coefficients, multiply both sides by 4:

4 C_3H_5N_3O_9 (l)\rightarrow 6N_2 (g) + O_2 (g) + 10 H_2O (g) + 12 CO_2 (g)

Question 2 (b). Now we can make use of the balanced chemical equation and apply it for the context of this separate problem. We're given the following variables:

V_{CO_2} = 41.0 L

T = -14.0^oC + 273.15 K = 259.15 K

p = 1 atm

Firstly, we may find moles of carbon dioxide produced using the ideal gas law pV = nRT.

Rearranging for moles, that is, dividing both sides by RT (here R is the ideal gas law constant):

n_{CO_2} = \frac{pV_{CO_2}}{RT} = \frac{1 atm\cdot 41.0 L}{0.08206 \frac{L atm}{mol K}\cdot 259.15 K} = 1.928 mol

According to the stoichiometry of the balanced chemical equation:

4 C_3H_5N_3O_9 (l)\rightarrow 6N_2 (g) + O_2 (g) + 10 H_2O (g) + 12 CO_2 (g)

4 moles of nitroglycerin (ng) produce 12 moles of carbon dioxide. From here we can find moles o nitroglycerin knowing that:

\frac{n_{ng}}{4} = \frac{n_{CO_2}}{12} \therefore n_{ng} = \frac{4}{12}n_{CO_2} = \frac{1}{3}\cdot 1.928 mol = 0.6427 mol

Multiplying the number of moles of nitroglycerin by its molar mass will yield the mass of nitroglycerin decomposed:

m_{ng} = n_{ng}\cdot M_{ng} = 0.6427 mol\cdot 227.09 g/mol = 146.0 g

3 0
4 years ago
Other questions:
  • Which of the following has mass? A. Matter B. Force C. Space D. Light
    7·2 answers
  • What are the roles of producers,consumers, and decomposers in an ecosystem?
    13·2 answers
  • If you have a small mineral sample, why might testing for cleavage be one of the last things you do?
    8·1 answer
  • At 27°C, 2.40g of a certain gas occupies a volume of 9.84 L at a pressure of 172 torr. Calculate the molar mass of the gas.
    11·1 answer
  • HELP ITS OVER DUE AND GRADE BOOK ENDS MARCH 5TH
    5·1 answer
  • 1 what do you understand by the term isotopes 2 why do I should talk of an element process identical chemical properties 3 name
    11·1 answer
  • #1/ 81.8 grams carbon 18.2 grams hydrogen molar mass 132.0g/mol.
    10·1 answer
  • It is a homogenous mixtur of two or more pur substances
    7·1 answer
  • CH3CHClCH(CH3)CH2CH2CH2CH2Br name the molecule iupac rules please
    10·1 answer
  • The energy levels of the positive ions that have just a single electron, like He , Li2 , or Be3 , etc., follow the formula Bohr
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!