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Marina CMI [18]
3 years ago
15

Which term refers to science that can be used to solve problems?

Physics
2 answers:
larisa [96]3 years ago
7 0
I think Physical science because basic wouldn't or applied or biology
Sergeeva-Olga [200]3 years ago
4 0

Answer: B

Explanation:

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B. The number of field lines on the source charge.
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Julie drives 100 mi to Grandmother's house. On the way to Grandmother's, Julie drives half the distance at 44.0mph and half the
sashaice [31]

Answer:

52.47706 mph

54.5 mph

Explanation:

The average speed is given by

V_{av}=\dfrac{Distance}{Time}

V_{av}=\dfrac{100}{\dfrac{50}{44}+\dfrac{50}{65}}\\\Rightarrow V_{av}=52.47706\ mph

Julie's average speed on the way to Grandmother's house is 52.47706 mph

V_{av}=\dfrac{44+65}{2}\\\Rightarrow V_{av}=54.5\ mph

Average speed on the return trip is 54.5 mph

4 0
4 years ago
A hot air balloon is filled with 1.45 × 10 6 L of an ideal gas on a cool morning ( 11 ∘ C ) . The air is heated to 109 ∘ C . Wha
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Answer:

<em>The volume of air after the balloon is heated = 1.95 × 10⁶ L</em>

Explanation:

Charles Law: Charles' law states that the volume of a given mass of gas is directly proportional to the temperature in Kelvin, provided that the pressure remains constant.

It can be expressed mathematically as,

V₁/T₁ = V₂/T₂

Making V₂ The subject of the equation

V₂ = (V₁/T₁)T₂.................... Equation 1

Where V₁ = Initial Volume, T₁ = Initial Temperature, V₂ = Final Volume, T₂ = final Temperature

<em>Given: V₁ = 1.45 × 10⁶ L, T₁ = 11 °C = (11 + 273) K = 284 K, T₂ = 109 °C = (109 + 273) = 382 K.</em>

<em>Substituting these values into equation 1 above,</em>

<em>V₂ = (1.45×10⁶)382/284</em>

<em>V₂ = 1.95 × 10⁶ L</em>

<em>Therefore the volume of air after the balloon is heated = 1.95 × 10⁶ L</em>

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which of the four terms below includes the other three terms (1)community (2)ecosystem (3)population (4)individuala
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You are at a furniture store and notice that a Grandfather clock has its time regulated by a physical pendulum that consists of
artcher [175]

Answer:

The distance is 1.026 m.

Explanation:

mass of rod, M = 1.23 kg

Length, L = 1.25 m

mass, m = 10 kg

Time period, T = 2 s

Let the distance is d.

The formula of the time period is given by

T = 2\pi\sqrt\frac{\frac{1}{3}ML^2+md^2}{(M +m)g}\\\\2\times 2 = 4\pi^2\times \frac{\frac{1}{3}\times1.23\times1.25\times 1.25+ 10d^2}{(1.23 + 10)\times9.8}\\\\11.16  = 0.64 + 10d^2\\\\d= 1.026 m

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3 years ago
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