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Alexandra [31]
3 years ago
15

In a beaker a compartment a has 25% glucose solution and compartment b has 5% glu glucose solution. The membrane is permeable to

the solvent but not to the solute. What transport mechanism causes water to move from a to
Chemistry
1 answer:
dem82 [27]3 years ago
7 0

Answer is: osmotic pressure.

The direction of osmotic pressure is always from the side with the lower concentration of solute to the side with the higher concentration, in this example, from solution b (5% glucose) to solution b (25% glucose).

Osmotic pressure, alongside the vapor pressure depression, freezing point depression and the boiling point elevation are the colligative properties od solution.

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The value of the equilibrium constant for a reaction is 2.65 x 10-6 at 35° Calculate the value of LaTeX: \DeltaΔG°rxn.
stealth61 [152]

Answer:

The answer is "33.95 \bold{ \frac{kj}{mol}}\\".

Explanation:

Formula:

\bigtriangleup G_0= -R \times T l_n \times K_{eq}\\

where

K_{eq}  = \text{equilibrium constant}\\

Given value:

T =35^{\circ} C\\

convert temperature celsius (°C) to Kelvin (K):

= (273+45) \ kelvin \\\\= 318 \ Kelvin \\\\= 318 \ K

R = 8.314 \ \ \frac{J}{ mol \cdot K}

\bigtriangleup G_0= -(8.314 ) \times 31.8 \times  l_n (2.65\times 10^{-6})\\

        =-(8.314 ) \times 31.8T l_n \times (2.65\times 10^{-6})\\\\

After solving the value it will give:

        = 33.95  \bold{ \frac{kj}{mol}}\\

3 0
3 years ago
What are examples of actinides
lilavasa [31]

Answer:

Neptunium, Protactinium, plutonium and more

Explanation:

4 0
3 years ago
Which is the following will have the highest vapor pressure
Alexus [3.1K]

There is no list, but possibly evaporation.

8 0
3 years ago
657 g of 2-chloro-2,4-dimethylpentane (g/mol = 134.65) is generated from a reaction between 2,4-dimethyl-2-pentanol (g/mol = 116
jasenka [17]
For a 100% yield 761.31 g of <span>2-chloro-2,4-dimethylpentane will be produced.</span>

5 0
3 years ago
How much salt (NaCl) is carried by a river flowing at 30.0 m3/s and containing 50.0 mg/L of salt
denis23 [38]

Answer:

129,600kg/day

Explanation:

The river is flowing at 30.0

1 m³ is equivalent to 1000L

flowrate of river = 30*1000 =30,000L/s

Convert L/s to litre per day by multiplying by 24*60*60

flowrate of river = 30,000 * 24*60*60 L/day

                    = 2,592,000,000L/day

if the river contains 50mg of salt  in 1L of solution

lets find how many mg of salt Y is contained in 2,592,000,000L/day

by cross multiplying we have

Y=\frac{2592000000*50}{1}

Y= 129,600,000,000 mg/day

convert this value to kg/day by dividing by 1 million

Y= 129,600,000,000/1000000

Y= 129,600kg/day

3 0
3 years ago
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