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marin [14]
3 years ago
6

An object falls with an acceleration of 9.8 m/s2. What is its speed after 2 s?

Chemistry
1 answer:
Iteru [2.4K]3 years ago
5 0
Acceleration is the rate at which velocity changes; here we are told the speed increases by 9.8m/s for each second of travel

assuming the object starts at rest, the object has a speed of 9.8m/s after one second, and a speed of 19.6m/s after two

mathematically, we write

v= at

where v is the velocity, a is the acceleration and t is the time of travel

so v= at = 9.8m/s/s x 2s = 19.6m/s
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Which statements explain the relationship between mass, velocity and kinetic energy? Select the TWO (2) that apply.
Ad libitum [116K]

Answer:

I think D

Explanation:

Kinetic energy has a direct relationship with mass, meaning as mass increases so does the kinetic Energy of an object.

6 0
2 years ago
A solution is made by dissolving 0.611 mol of NaCl in 250 g of water. If the molar mass of NaCl is 58.44 g/mol, what is the mola
shusha [124]
Molality= moles NaCl/ Kg H2O

250 g (1 Kg/ 1000 grams)= 0.250 Kg

Molality= 0.611 moles/ 0.250 Kg= 2.44 molal
6 0
3 years ago
Read 2 more answers
A solution is made by mixing equal masses of methanol, CH 4 O , and ethanol, C 2 H 6 O . Determine the mole fraction of each com
Fynjy0 [20]

Answer:

Mole fraction of CH_4O = 0.58

Mole fraction of C_2H_6O = 0.42

Explanation:

Let the mass of CH_4O and C_2H_6O = x g

Molar mass of CH_4O = 33.035 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles_{CH_4O}= \frac{x\ g}{33.035\ g/mol}

Moles_{CH_4O}=\frac{x}{33.035}\ mol

Molar mass of C_2H_6O = 46.07 g/mol

Thus,

Moles= \frac{x\ g}{46.07\ g/mol}

Moles_{C_2H_6O}=\frac{x}{46.07}\ mol

So, according to definition of mole fraction:

Mole\ fraction\ of\ CH_4O=\frac {n_{CH_4O}}{n_{CH_4O}+n_{C_2H_6O}}

Mole\ fraction\ of\ CH_4O=\frac{\frac{x}{33.035}}{\frac{x}{33.035}+\frac{x}{46.07}}=0.58

Mole fraction of C_2H_6O = 1 - 0.58 = 0.42

6 0
3 years ago
You have an unknown quantity of oxygen at a pressure of 2.2 atam, a volume of 21 liters and a temperature of 87 Celsius. How man
laila [671]

<span>Let's assume that the oxygen gas has ideal gas behavior. 
Then we can use ideal gas formula,
      PV = nRT</span>


Where, P is the pressure of the gas (Pa), V is the volume of the gas (m³), n is the number of moles of gas (mol), R is the universal gas constant ( 8.314 J mol⁻¹ K⁻¹) and T is temperature in Kelvin.

<span>
P = 2.2 atm = 222915 Pa
V = 21 L = 21 x 10</span>⁻³ m³

n = ?

R = 8.314 J mol⁻¹ K⁻¹

<span> T = 87 °C = 360 K

By substitution,
</span>222915 Pa x 21 x 10⁻³ m³ = n x 8.314 J mol⁻¹ K⁻<span>¹ x 360 K
                                       n = 1.56</span><span> mol</span>

<span>
Hence, 1.56 moles of the oxygen gas are </span><span>left for you to breath.</span><span>
</span>
6 0
3 years ago
HELP PLZ
Vinvika [58]

Answer:

1). 19.9

2). 0

8 0
3 years ago
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