A 15.0 L tank of gas is contained at a high pressure of 8.20x10 4 torr. The tank is opened and the gas expands into an empty cha
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The question is incomplete, complete question is :
The frequency factors for these two reactions are very close to each other in value. Assuming that they are the same, compute the ratio of the reaction rate constants for these two reactions at 25°C.
Activation energy of the reaction 1 , = 14.0 kJ/mol
Activation energy of the reaction 2, = 11.9 kJ/mol
Answer:
0.4284 is the ratio of the rate constants.
Explanation:
According to the Arrhenius equation,
The expression used with catalyst and without catalyst is,
where,
= rate constant reaction -1
= rate constant reaction -2
Activation energy of the reaction 1 , = 14.0 kJ/mol = 14,000 J
Activation energy of the reaction 2, = 11.9 kJ/mol = 11,900 J
R = gas constant = 8.314 J/ mol K
T = temperature =
Now put all the given values in this formula, we get
0.4284 is the ratio of the rate constants.
Explanation:
Reaction equation showing alpha decay in Uranium-238 is as follows.
It is known that an alpha particle is basically a helium nucleus and it contains 2 protons and 2 neutrons.
Symbol of an alpha particle is .
As atomic mass or weight is the sum of total number of protons and neutrons present in an atom.
Hence, the atomic weight of the alpha particle is (2 + 2) = 4.