Answer:
2.5m/s2
Explanation:
The following were obtained from the question:
F = 600N
M = 240 kg
a =?
Recall: F = Ma
a = F/M
a = 600/240
a = 2.5m/s2
Therefore, the acceleration of the motorcycle is 2.5m/s2
The force of the tripped catch exerted on the 2.5 Kg ball moving at 8.5 m/s to the Left is 160 N
<h3>Data obtained from the question </h3>
- Initial velocity (u) = 8.5 m/s
- Final velocity (v) = 7.5 m/s
- Time (t) = 5 ms = 0.25 s
- Mass (m) = 2.5 Kg
- Force (F) = ?
<h3>How to determine the force</h3>
The force exerted on the ball can be obtained as follow:
F = m(v + u) / t
F = [2.5(7.5 + 8.5)]/ 0.25
F = 40 / 0.25
F = 160 N
Thus, the force exerted on the ball is 160 N
Learn more about momentum:
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Answer:
hmm if it were up to me i would say gravity potential energy and sorry I don't really have a third one hope this helps though.
Six centimeters equal to about two inches
